<span>let
x = acres of when
y = acres of rye
Maximize
z = 500x + 300y
subject to
x >= 3
x <= 15
y >= 1
y <= 7
x + y <= 20
bounded
both
(3, 1)
(15, 1)
(15, 5)
(13, 7)
(7, 3)
sub points into your max equation
(3, 1) = 1500 + 300 = 1800
(15, 1) = 7500 + 300 = 7800
(15, 5) = 7500 + 1500 = 9000
(13, 7) = 6500 + 2100 = 8600
(7, 3) = 3500 + 900 = 4400
max profit of $9,000 is achieved when 15 acres of wheat and 5 acres of rye are planted and sold</span>
In the x quarts of 2% fat milk, there is 0.02x quarts of fat.
in the y quarts of 4% fat milk there is 0.04y quarts of fat.
together, there is (x+y) quarts of milk, and 0.24 quarts of fat.
the equations are:
x+y=9
0.02x+0.04y=0.24
multiply the first equation with 0.02: 0.02x+0.02y=0.18
subtract this new equation from equaition 2 to eliminate x:
0.04y-0.02y=0.24-0.18
0.02y=0.06
y=3
x=9-3=6
x is twice as much as y.
He used twice as much as the 2% fat milk than the 4% fat milk.
so the first choice is the correct answer.
