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3 years ago

You flip a coin and roll a dice.what is the probabiliy the coin lands on heads and the dice lands on a number less than 5?

Mathematics

2 answers:

Luden [163]3 years ago

5 0

Answer:

Step-by-step explanation:

The coin would be 1/2 and the dice one would be 4/6 unless you're including the number 5 then it would be 5/6

slamgirl [31]3 years ago

5 0

Answer:

On a coin, the probability of heads: 1/2

ON a die, the probability of getting a number less than 5 : 4/6

1 /2 × 4 /6 = 1/3

THE ANSWER IS 1/3

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sara drives 117 miles on 5.2 gallons of gas.she uses this information to calculate how many miles per gallon she can drive. usin

Vesnalui [34]

I think its 270 miles per gallon

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2 years ago

A civil engineer is designing a public parking lot for the new town hall. The number of cars in each row should be six less than

Alexandra [31]

The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars

Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:

y = x - 6 (1)

The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:

xy = 112 (2)

Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.

Using the value of y from equation 1 to 2, we get:

x(x - 6) = 112 (3)

This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.

6 0

2 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

2 years ago

HELP!!! NEED HELP!!!!

blsea [12.9K]

Answer:

Step-by-step explanation:

6 0

2 years ago

2w-6+w+5 how do you work this problem

sergejj [24]

You combine the numbers that have the same letter attached to them. Then you add or subtract the bumbers from each other to. After that you make the numbers and the numbers with letters into one equation

Ex: 13+5r+7r= 13+12r

Step-by-step explanation:

2w+w=3w If theres a letter by itself it means theres a 1.

6 0

2 years ago