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Lena [83]
3 years ago
9

Draw triangle ABC by first drawing segment BC six inches long. Then draw a 60° angle at vertex B and a 60° angle at vertex C. Ex

tend the segments so that they intersect at point A.
Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that segment BC is the base of the triangle, this drawing shows that triangle ABC is an equilateral triangle.

Since;

<B = <C = 60°

Then,

<A + <B + <C = 180^{o}

<A + 60° + 60° = 180^{o}

<A = 180^{o} - 120^{o}

    = 60°

Thus,

AB = BC = AC = 6 inches

The construction is attached to this answer.

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Evaluating the second function;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}

simplifying further;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}

Therefore, we have;

undefined

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