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professor190 [17]
3 years ago
8

It cost Jocelyn $5.60 to send 56 text messages. How much would it cost to send 198 text messages?

Mathematics
2 answers:
-BARSIC- [3]3 years ago
6 0

Answer:

$19.80

Step-by-step explanation:

56÷5.60=.10

.10×198=19.8

dybincka [34]3 years ago
3 0

Answer:

$19.80

Step-by-step explanation:

First, the unit rate of each text message is .1 so if we multiply 198 x .1 we get $19.80 which is your answer.

Hope this helps!

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Which number is closest to -1?
Katyanochek1 [597]

Answer:

1. -0.82     2. -0.28

Step-by-step explanation:

4 0
3 years ago
A machine depreciate in value at the rate of 10% every year on reducing balance. if the original cost is 20000 and the scrapped
Aleonysh [2.5K]
Mark Brainliest please


Answer: 10 years

Explanation:


The original cost of the machine = 20000

The scrap value of the machine = 13122

Value of the machine = ( 20000 - 13122 ) = 6878

Depreciation of the machine for the first year = ( 6878 * 10 % )
= 687.8
So, the effective life of the machine is = ( 6878 / 687.8 )
= 10 years
7 0
3 years ago
Katie divided 4.25 by 0.25 and got a quotient of 0.17 what is wrong?
nalin [4]
It should be 17 because 4.25 divided by 0.25 is the same as 425/25 which is 17.
8 0
4 years ago
Read 2 more answers
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Liula [17]

Answer:

Arranging : 9.2020 < 9.2200 < 9.2211 < 9.8000

Step-by-step explanation:

9.22   = 9.2200

9.202 = 9.2020

9.8      = 9.8000

9.2211  = 9.2211

Now compare the numbers in the tenths : except 3rd option ( 8 in the tenth place) everything has 2 in the tenths place.

Arranging : 9.2200, 9.2020, 9.2211, 9.800

So we take the next place, hundredths : Compare the number in hundredth place and tenth place and arrange. [ 22, 20, 80 , 22]

Arranging : 9.2020 , 9.2200, 9.2211, 9.8000

Now compare  the numbers in tenths , hundredths and thousandth place :

[220, 202, 800, 221 ]

Arranging : 9.202, 9.220, 9.221, 9.800

Now compare all the four numbers and arrange :

[ 2200, 2020 , 8000, 2211 ]

Arranging : 9.2020 , 9.2200 , 9.2211 , 9.8000

5 0
4 years ago
A classroom has a length of 20ft. And width of 30ft. The flooring Is to be replaced by tiles. If each tile has a length of 24in.
umka21 [38]
Area of the floor is 60ft^2. (20x30=60ft)
Each tile is 6ft^2 in area.
24in = 2ft
36in = 3ft

60/6= 10 tiles 
3 0
4 years ago
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