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Doss [256]
2 years ago
11

I need help on this question

Mathematics
1 answer:
xxMikexx [17]2 years ago
4 0
I think it’s B but I’m not 100%
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On a vacation in Puerto Rico, Rose jumped off a cliff into a river in EL Yunque Forest Reserve. Her height as a function of time
Nonamiya [84]
H(t) = -16t² + 16 t + 480

Factor out -16
-16(t² - t - 30) 
t² - t - 30 
(t + 5)(t - 6) ⇒ t(t-6) + 5(t-6) ⇒ t² -6t + 5t - 30 ⇒ t² - t - 30

t + 5 = 0           t - 6 = 0
t = -5                t = 6

The value of t is either -5 or 6 however time can't be measured in negative form; then, it took Rose 6 seconds to hit the water.


3 0
3 years ago
Which of these is true and why
LuckyWell [14K]

Answer:

Step-by-step explanation:

True statements

All equallateral triangles are similar. Their sides are all in the same ratio when comparred.

All squares are similar. Same reason as equilateral triangles. All sides to both squares compared are the same.

False Statements

Isosceles triangles can and usually do have different base angles.

rectangles can have all sorts or side lengths. The only requirement is consecutive sides form right angles.

2 rhombuses can have side lengths that are in the same ratio, but the heights are not in the same ratio. That eleminates.

Answer

These are the only true ones: Statements 2 and 5 are true. The rest are not.

7 0
1 year ago
Find the X intercepts of the equation f(x) = x^2 - 6x + 6
Arturiano [62]

Answer:

x-intercepts = (x ≈ -0.87), (x ≈ 6.87)

Step-by-step explanation:

let x = 0, in equation for x-intercepts

solve for x using the

quadratic formula

x = <u>−6 ± √ 36 + 24 </u>

               2x

= <u>−6 ± √60</u>

         −2x

 = <u>−6 ± 2 √ 15</u>

           −2           = 3 ± √15

8 0
3 years ago
Answer Please this is really important
trapecia [35]

Answer:

B) Parallel

Step-by-step explanation:

The lines have the same slope of \frac{4}{3}. This makes the lines parallel.

Hope it helps!

3 0
3 years ago
Read 2 more answers
Find the coefficient of the x^3 in the expansion of (2x-9)^5
il63 [147K]

Use the binomial theorem:

\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}

The <em>x</em> ³ terms occurs for 5 - <em>k</em> = 3, or <em>k</em> = 2, and its coefficient would be

\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}

8 0
2 years ago
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