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densk [106]
3 years ago
6

Choose Yes or No to tell if the fraction

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

yes

yes

no

yes

Step-by-step explanation:

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The length of a rectangular pool is 50 yards, and the width of the pool is 16 yards. What is the approximate length of the diago
melisa1 [442]

Answer:

52.5

Step-by-step explanation:

You would use the Pythagorean theorem to solve this. Using the formula,

a^2 + b^2 = ^2

You would have an equation of 50^2 + 16^2 = c ^2.

50^2 is 2500, and 16^2 is 256.

There, you have 2500+256 = c^2

add those together, and you have 2756.

Now, you have to find the square root of 2756 (to solve 2756 = c^2)

which leaves you with 52.4976189936 . Rounded to the nearest tenth, you end up with 52.5.

4 0
3 years ago
The perpendicular distance of p (3,4) from the y - a x is _____​
solmaris [256]

Answer:

a

Step-by-step explanation:

The perpendicular distance from the y- axis is the value of the x- coordinate, so

perpendicular distance is 3 units

8 0
3 years ago
Eric took a test. All the questions have equal value. He answered 38 of the questions correctly.
Archy [21]

Answer:

72% your welcome lolbrhdhhdvdceuegcstditdti

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME FOR BRAINLIEST!!!!
vekshin1

Answer:

A=52.8 miles (approximately)

Step-by-step explanation:

We can assume that this triangle is not a right angle, therefore we cannot use Pythagorean theorem.  Let's use the Law of Sines:

\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}


Where A is unknown, a=28 miles, b=32 miles, B=87°

Therefore by law of sines we have:

\frac{sin(A)}{28} =\frac{sin(87)}{32} \\

By multiplying 28 to Isolate sin(A) we have:

sin(A)=\frac{28*sin(87)}{32}

To cancel out sine on the right, we must multiply both by the inverse sine and so:

A=sin^{-1}(\frac{28*sin(87)}{32})=52.7658\\ \\A=52.8mi

8 0
3 years ago
suppose that, and an equation with two variables, you know the value of one of the variables. Describe a method for finding the
statuscvo [17]
So if an equation with two variables, you need to also two equations to solve the values of the variables. but if you knew the value of the one variable then onl one equation is need. for example an equation x + y = 20
where x = 5
then to solve the value of y, substitute the value of the equation
5 + y = 20
then transpose 5 to the other side
y = 20 - 5
y = 15
7 0
3 years ago
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