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kondor19780726 [428]
3 years ago
11

PLZZZZZ HELP ME WHOEVER ANSWERS FIRST CORRECTLY I WILL MAKE BRAINLIESTTTT

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0
A is congruent to D
B is congruent to E
C is congruent to F

Hope this helped :)
You might be interested in
What are the odds that the spinner lands on red or the number 4?<br> 4<br> 4<br> 2<br> 33
uranmaximum [27]

Answer:

5 to 3

Step-by-step explanation:

The desired outcomes are 4 or red.

Here are all the possible outcomes:

1 red

1 red

1 red

2 green

3 blue

3 blue

4 yellow

4 yellow

The desired outcomes are in boldface. There are 5 desired outcomes.

There are 3 outcomes that are not desired.

odds of 4 or red = 5 to 3

4 0
3 years ago
Read 2 more answers
Find the measurement of angle A
dolphi86 [110]
4x+17+x+23+80=180. Now combine like terms.

5x+120=180
5x=60
X=12
6 0
3 years ago
what does y =mx +b mean and how do you use it to solve problems? whats the different between y=mx+b and y=mx + c
algol13

y=mx+c is the equation for a line graph, m is the gradient and c is where it goes through the y axis, the only difference between y=mx+c and y=mx+b is where u live as in different countries learn it different ways but it is still the same thing
4 0
4 years ago
What is the range of the function graphed below?
Dmitriy789 [7]

Answer:

Negative 3 less-than y less-than-or-equal-to 3

Step-by-step explanation:

By looking at a coordinate plane, we can easily see the range

remember, a closed dot means includes , and an open dot means does not include

[closed dot]

(open dot)

the range is all possible y-values. so, all y values shown are

3               which it includes

to -3            which it excludes  / does not include

so, all y values are greater than -3 and less than or equal to 3

7 0
2 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
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