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3 years ago

Find the solution to the system 9x−4y=−13 and 9x−2y=−20

Mathematics

1 answer:

BaLLatris [955]3 years ago

3 0

Answer:

x = -3, y = -3.5. As an ordered pair it is (-3, -3.5).

Step-by-step explanation:

9x − 4y = −13

9x − 2y = -20

Subtract:-

-2y = 7

y = -3.5.

Substitute for y in the first equation:

9x - 4(-3.5) = -13

9x = -27

x = -3.

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Find the slope of a line with ordered pairs (1,5) and (5,8)

klemol [59]

Step-by-step explanation:

(1,5) (5,8)

x,y. x,y

Formula: y2-y1

x2-x1

so...

8-5= 3

5-1 = 4

so... 3

6 0

2 years ago

Write the slope intercept form of the equation of the line through the given points

garri49 [273]

Answer:

9) y = -3x - 4

10) y = -1/3x + 14/3

11) y = x - 1

12) y = -7/5x - 18/5

13) y = 3/5x + 9/5

14) y = -2x - 3

Step-by-step explanation:

For this explanation, let's use the last problem as the example. You would use the formula y=mx+b. The first thing you would need to find would be the slope, or m. So, you would find the slope and conclude the answer is -2. After that, you would solve for b and get the answer. Hope this helped!

4 0

2 years ago

What is the 51st term of the arithmetic sequence 29,9,-11

valina [46]

Answer:

-951

Step-by-step explanation:

an=a1+(n−1)d

\begin{gathered}29 = a_1 + (1-1)d\\29 = a_1\\9 = 29 + (2-1)d\\9 = 29 + d\\d = -20\\a_n = 29 -20 (n-1)\\a_n = 29 - 20n+20\\a_n = -20n + 49\\\\a_51 = -20(51) + 49 = -951\end{gathered}29=a1+(1−1)d29=a19=29+(2−1)d9=29+dd=−20an=29−20(n−1)an=29−20n+20an=−20n+49a51=−20(51)+49=−951

6 0

2 years ago

HELP ASAP IM IN A LIVE LESSON

Charra [1.4K]

Answer: 70 Degrees

Step-by-step explanation:

65+45=110

180-110=70 degrees

7 0

2 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago