To solve this equation we must first plug in 5 for x.
<span> (5 - 4x)
</span>↓
(5 - 4 · 5)
The next step would be to multiply 4 by 5 to get rid of the parenthesis within our main parenthesis.
(5 - 4 · 5)
(5 - 20)
The next step would be to subtract both of the numbers within the parenthesis.
(-15)
Now we must multiply.
-
· 15 = -
-
Now we simplify our answer to get our final answer.
-5
Answer: V = l w h
Step-by-step explanation:
Hi, to answer this question we have to apply the formula for the volume of a rectangular prism.
Volume of a rectangular prism (V) = Length x Width x Height
Replacing with the values given:
V = l w h
All values are multiplied (didn’t use x as a multiplication symbol to avoid confusion)
Feel free to ask for more if needed or if you did not understand something.
Answer:
hey
Step-by-step explanation:
to calculate perimeter, you require length,breadth
since points are given,find distance between points using distance formulae
<h2>root over (x2-x1)² +(
y2-y1)²</h2>
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<h3>Point H =(6,7)</h3><h3>Point I=(-6,-9)</h3><h3>Point J=(-10,-6)</h3><h3>Point G=2,10)</h3>
Now find distance between HI and IJ
HI gives the distance - length of rectangle
IJ gives the distance - breadth of rectangle
use the formulae ,2(length+breadth) to get perimeter
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HI= root over 144+256= root 400
HI=20
IJ= root over 16+9= root 25
IJ=5
PERIMETER =2(20+5)
2×25
=50
Answer:
1. Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).
(a) Factor the given expression using the GCF monomial.
(b) Factor the given expression using the difference of squares.
DO NOT ANSWER UNLESS YOU CAN EXPLAIN THIS TO ME CORRECTLY
Answer:
The points are randomly scattered with no clear pattern
The number of points is equal to those in the scatterplot.
Step-by-step explanation:
The points in the residual plot of the line of best fit that is a good model for a scatterplot are randomly scattered with no clear pattern (like a line or a curve).
The number of points in the residual plot is always equal to those in the scatterplot.
It doesn't matter if there are about the same number of points above the x-axis as below it, in the residual plot.
The y-coordinates of the points are not the same as the points in the scatterplot.
