Answer:
third option
Step-by-step explanation:
Given
x² + 4x - 4 = 0 ( add 4 to both sides )
x² + 4x = 4
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(2)x + 4 = 4 + 4, that is
(x + 2)² = 8 ( take the square root of both sides )
x + 2 = ± 
= ± 2
( subtract 2 from both sides )
x = - 2 ± 2
Answer:
The answer is 365
Step-by-step explanation:
just do 73 times 5 and you get your answer
Answer:
The answer is
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
Q(2,4) and R(-3,9)
The midpoint is
We have the final answer as
Hope this helps you
A. This is the original equation: 2x + 3 - 1 = x + 5
b. 2x + 2 = x + 5 ← combined like terms on left side
2x + 2 - 2 = x + 5 - 2 ← used inverse operation to collect constants on right side
2x = x + 3 ←simplified each side
2x - x = x - x + 3 ←used inverse operation to collect variable terms on left side
x = 3 ← simplified each side
answer x = 3
c. 2(3) + 3 - 1 = 3 + 5
6 + 3 - 1 = 8
9 - 1 = 8
8 = 8
<span>a2 – b2 = (a + b)(a – b) or (a – b)(a + b).
This is the 'Difference of Squares' formula we can use to factor the expression.
In order to use the </span><span>'Difference of Squares' formula to factor a binomial, the binomial must contain two perfect squares that are separated by a subtraction symbol.
</span><span>x^2 - 4 fits this, because x^2 and 4 are both perfect squares, and they are separated by a subtraction symbol.
All you do here to factor, is take the square root of each term.
√x^2 = x
√4 = 2
Now that we have our square roots, x and 2, we substitute these numbers into the form (a + b)(a - b).
</span>
<span>(a + b)(a - b)
(x + 2)(x - 2)
Our answer is final </span><span>(x + 2)(x - 2), which can also be written as (x - 2)(x + 2), it doesn't make a difference which order you put it in.
Anyway, Hope this helps!!
Let me know if you need help understanding anything and I'll try to explain as best I can.</span>
