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lara [203]
3 years ago
12

Find the area of a parallelogram with the given vertices. P(1, 3), Q(3, 3), R(7, 8), S(9, 8) A. 10 units2 B. 5 units2 C. 20 unit

s2 D. none of these
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0

10 units squared should be your answer


zysi [14]3 years ago
6 0
The area of a parallelogram, like a rectangle, is base times height. The base is 2 units. the height is 5 units, from y=3 to y=8
2 * 5 = 10
The area therefore, is A) 10 units.<span />
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3 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

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We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


5 0
3 years ago
Is 56 a multiple of 6?
andreyandreev [35.5K]

Good evening ,

_______

Answer:

No

____________________

Step-by-step explanation:

A number is a multiple of 6 if it can be divided by 6 .

Since 3 don’t divide 56 because 5 + 6=11 and 3 don’t divided 11 ,

Then 6 don’t divide 56

then , 56 isn’t a multiple of 6.

:)

3 0
3 years ago
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