What is the correct domain and range in set notation
1 answer:
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Answer:
59.0°
Step-by-step explanation:
Many triangle solvers are available for your phone, tablet, or browser. The attachments show the input and output of one of them.
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You can use the law of cosines to compute the result yourself.
b^2 = a^2 + c^2 - 2ac·cos(B)
cos(B) = (a^2 +c^2 -b^2)/(2ac) = (22^2 +18^2 -20^2)/(2·22·18) = 408/792
B = arccos(408/792) ≈ 58.9924° ≈ 59.0°
I figured it out
warning: mildly incoherent math logic ahead
ok, so if you want a parabola facing right, then
first I'll solve for up down standard parabola then reflect across x=y line
so
y=ax²+bx+c
so let's say teh vertex is at the origin
that means when x=0, y=0
0=0
c=0
y=ax²+bx
ok, see diagram
we have some points, (0,0) and (11,0.5) and (-11,0.5)
use those oints to find a and b
0.5=121a+11b
0.5=121a-11b
add dem equations
1=242a
divide by 242
1/242=a
subsitute
0.5=121a+11b
0.5=121(1/242)+11b
0.5=0.5+11b
0=11b
0=b
oook
de equaiton is
if we want it facing right
switch x and y
the equation is or 
or or 
depends which way you want it and if you want f(x) or f(y) or x or y
warning: mildly incoherent math logic ahead
ok, so if you want a parabola facing right, then
first I'll solve for up down standard parabola then reflect across x=y line
so
y=ax²+bx+c
so let's say teh vertex is at the origin
that means when x=0, y=0
0=0
c=0
y=ax²+bx
ok, see diagram
we have some points, (0,0) and (11,0.5) and (-11,0.5)
use those oints to find a and b
0.5=121a+11b
0.5=121a-11b
add dem equations
1=242a
divide by 242
1/242=a
subsitute
0.5=121a+11b
0.5=121(1/242)+11b
0.5=0.5+11b
0=11b
0=b
oook
de equaiton is
if we want it facing right
switch x and y
the equation is
depends which way you want it and if you want f(x) or f(y) or x or y