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vivado [14]
3 years ago
15

I am having trouble with this question. ​

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

x=12√2

y=45°

Step-by-step explanation:

as we know diagonal of a square

=a√2

=12√2

and

y=45°

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What is the solution of a - 3 = -7
olga55 [171]

Answer:

-4

Step-by-step explanation:

take -3 to other side or        add 3 to both sides

So, a=-7+3

       =-4

7 0
3 years ago
Given a standard deck of cards, what is the probability of drawing a face card, given that it is a red card?
Svetllana [295]
A standard deck of cards has 54 cards, but only 26 of them are red. there are 6 red face cards, so the probability is 6/26 which is 3/13
6 0
4 years ago
Given the set definitions below, find X Y. X = {100, 200} Y = {1,2}
Veseljchak [2.6K]
The Cartesian product of two sets can be defined as the following: the set of all possible pairs where the 1st coordinate is an element of the 1st set and the 2nd coordinate is the element of the 2nd set. This has an obvious generalization for n sets (the cartesian product has then n coordinates).
Let us pick now all the pairs that have 100 as their first coordinate. We then have 2 choices for the 2nd coordinate, 1 and 2. Hence, the 2 pairs are: (100,1), (100,2). Similarly, if 200 is the first coordinate, the pairs are (200,1), (200,2).
These 4 pairs are the cartesian product (we have 4 pairs =2 elements from X* 2 elements from Y) .
It helps to remember that the cartesian product has as many elements as the product of the number of elements of each set.
4 0
3 years ago
Help me answer this ty
Ratling [72]

Answer:

c = 10 feet

Step-by-step explanation:

c =  \sqrt{ {8}^{2} +  {6}^{2}  }  \\ c =  \sqrt{64 + 36}  \\ c =  \sqrt{100}  \\ c = 10 \: ft

6 0
3 years ago
The terminal velocity of a person falling through air is about 100Km/hr. The acceleration due to gravity is 10ms−2. Use this inf
Aleonysh [2.5K]

The question here is how long does it take for a falling person to reach the 90% of this terminal velocity. The computation is:

The terminal velocity vt fulfills v'=0. Therefore vt=g/c, and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the differential equation shows that the time needed to reach velocity v is 

t= ln [g / (g-c*v)] / c. 

With v=.9 vt =.9 g/c,

t = ln [10] /c = 6.4 sec.

8 0
4 years ago
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