2 years ago

I am having trouble with this question.

Mathematics

1 answer:

a_sh-v [17]2 years ago

8 0

Answer:

x=12√2

y=45°

Step-by-step explanation:

as we know diagonal of a square

=a√2

=12√2

and

y=45°

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<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

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Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

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$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

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I am having trouble with this question. ​

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