Answer:
Option A is correct.
Step-by-step explanation:
As we see the graph, we can say that the correct statement is :
A.)All repairs requiring 1 hour or less have the same labor cost. We can see that the coat from 0 hours to 1 hour is $50. So, the number of hours falling in this range has the same repairing cost.
B.) Labor costs the same no matter how many hours are used for a repair. This is wrong as the graph is increasing after 1 hour.
C.) Labor costs for a repair are more expensive as the number of hours increases. This is wrong as the hours are increasing from 0.25 to 0.5 then to 0.75 but they all have the same cost.
D.)There is no cost of labor for a repair requiring less than 1 hour. This is also wrong. The cost is $50.
Answer:
12.5%
Step-by-step explanation:
There are two types of spinners here and the outcome of them is independent. That means
P(odd number,C) = P(odd number) * P(C)
There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:
P(odd) = 2/(2+2)= 1/2= 50%
There are four letters and the desired outcome is C. The chance for C will be:
P(C)= 1/4= 25%
Then the chance will be:
P(odd number,C) = P(odd number) * P(C)
P(odd number,C) =50% * 25% = 12.5%
The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
brainly.com/question/11464095
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One weighs a pound and the other pounds away!
