Let x be the digit in the tens place and y be the digit in the ones place.
so, the digit is xy
<span>
The ten's digit of a two digit number is 1 more than 4 times the units' digit.
</span>x = 4y + 1
<span>63 is subtracted from the number, the order of the digits is reversed
</span>10x + y - 63 = 10y + x
9x - 9y = 63
x = 4y + 1 ------------ (1)
9x - 9y = 63 ---------- (2)
Sub (1) into (2)
9(4y + 1) - 9y = 63
36y + 9 - 9y = 63
27y = 63 - 9
27y = 54
y = 2 ------- sub into (1)
x = 4(2) + 1 = 9
x = 9, y = 2
The number is 92
<em><u>Question:</u></em>
The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3
Options:
x = negative 3
x = negative 1
x = 1
x = 3
<em><u>Answer:</u></em>
The value of x is 1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-2x + y = 8 ------- eqn 1
5x - y = -5 ------- eqn 2
The above equations are added to solve for "x"
Add eqn 1 and eqn 2
-2x + y + 5x - y = 8 - 5
Combine the like terms
-2x + 5x + y - y = 3
Add the like terms
3x + 0 = 3
3x = 3
Divide both sides of equation by 3
x = 1
Thus the value of x is 1
Answer:
y = 3 * 2 ^ x
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
7 x 13 (split 13 into 10 + 3)
= 7 x ( 10 + 3) (expand parentheses by distributive property)
= (7 x 10) + (7 x 3)
= 70 + 21
= 91
In a short answer, to find average you need to add it all up and divide by the number of things you added. Ex. say I want to find the average for my english class, my grades are 90, 98, 100, 87, and 70. I would start by adding them up to get 445. then since i have 5 grades, i would divide the sum 445 by 5 and get an 89 as my average.
(Everything in this answer is example only, not my real grades.)
