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romanna [79]
3 years ago
6

Help me please will give brainliestttt

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0

Step-by-step explanation:

a=2

b=4

c=x

a×b=c

2×4=8

c=8

answer is eight

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Ainat [17]
If you can use a calculator, enter (4/1/4)/(4/1/2) and you will get 1/2
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Question 3 (2 marks)
Sav [38]

Answer:

$3385 per week

Step-by-step explanation:

so, he gets $370 plus 4.5% of what he is selling.

$67000 = 100% of selling

1% = 100%/100 = 67000/100 = $670

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2 years ago
Someone help ! It’s talking about Integers !!
nataly862011 [7]

Step-by-step explanation:

  1. The numbers to the <u>right</u> of 0 are <u>positive</u>. The numbers to the <u>left</u> of 0 are <u>negative</u><u>.</u> 0 is neither positive nor negative.
6 0
3 years ago
Read 2 more answers
The accompanying table shows the number of bacteria present in a certain culture over a 6 hour period, where x is the time, in h
madam [21]

The number of bacteria present after 15 hours is 18928

<h3>How to determine the exponential equation?</h3>

An exponential equation is represented as;

y = ab^x

Where

a = y, when x = 0

From the table, we have:

y = 1796 when x = 0

So, we have:

y = 1796b^x

Also, we have the point (1, 2097)

This gives

2097 = 1796b^1

Divide by 1796

b = 1.17

Substitute b = 1.17 in y = 1796b^x

y = 1796(1.17)^x

This means that the exponential equation is y = 1796(1.17)^x

After 15 hours, we have:

y = 1796(1.17)^15

Evaluate

y = 18928

Hence, the number of bacteria present after 15 hours is 18928

Read more about exponential equation at:

brainly.com/question/23729449

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7 0
2 years ago
If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

6 0
3 years ago
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