Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
Start with the point-slope formula shown at the top in red.
Now, substitute your slope and coordinates in the formula.
Then distribute and combine lie terms.
Finally, add 2x to both sides to get your equation in standard form.
The answer would be Y1=0 y2=1/9
Given:
The values of a linear function are 
and 
.
To find:
The linear function.
Solution:
If a linear function passes through two points, then the equation of the linear function is:
The values of a linear function are and . It means the function passes through the points (-9,8) and (0,1). So, the equation of the linear function is:
Adding 8 on both sides, we get
Putting 
, we get
Therefore, the required linear function is .
