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Rasek [7]
3 years ago
5

PLEASE HELPPPPP ILL GIVE BRAINIEST ANSWER!!!this is Calculous (chain rule)!!​

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

Cn75 a is the answer that is if it is in advane studies math sorry if this is not what ya need

Step-by-step explanation:

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Alissa is analyzing an exponential growth function that has been reflected across the y-axis. She states that the domain of the
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i feel like u are going to delete this but if this helped please don't delete it the answer is, Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.

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Find the area of the parallelogram.
kotegsom [21]
You can see that the base is 5 units.
The height is 3.
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A = 5 * 3
A = 15 units^2

Hope this helps!

7 0
3 years ago
The table shows information about the number of sweatshirts sold and the money collected at a fundraiser for school athletic pro
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3 years ago
two triangles are similar. The base of the first triangle is 10 cm and the height is 15 cm. The base of the second triangle is 1
Andrei [34K]

Answer:

the height is 18cm

Explanation:

If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Are these ratios equal?

given that

Triangle 1 (first triangle)

base = 10cm

height = 15cm

Triangle 2 (second triangle)

base = 12cm

height = unknown

base 1 / base 2 = height 1 / height 2

10cm / 12cm = 15cm / xcm

xcm = 18cm

height = 18cm

8 0
4 years ago
Can anyone help me solve this? Please and thank you!
AveGali [126]

It's the sum of a geometric sequence.

Let's rewrite it a bit:

\displaystyle\\\sum_{n=1}^{10}8\left(\dfrac{1}{4}\right)^{n-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot \left(\dfrac{1}{4}\right)^{-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot 4=32\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n

And now let's calculate this sum \displaystyle \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n:

S_n=\dfrac{a(1-r^n)}{1-r}\\\\a=\dfrac{1}{4}\\n=10\\r=\dfrac{1}{4}\\\\S_{10}=\dfrac{\dfrac{1}{4}\cdot\left(1-\left(\dfrac{1}{4}\right)^{10}\right)}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{4}\cdot\left(1-\dfrac{1}{1048576}\right)}{\dfrac{3}{4}}=\dfrac{\dfrac{1048575}{1048576}}{3}=\dfrac{1048575}{3145728}=\\=\dfrac{349525}{1048576}

Now let's calculate the initial sum:

\displaystyle 32\cdot  \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n=32\cdot \dfrac{349525}{1048576}=\dfrac{349525}{32768}\approx10.67

8 0
2 years ago
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