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Gre4nikov [31]
3 years ago
6

El siguiente esquema representa un objeto con un volumen de 2cm^3 sumergido en un recipiente que contiene agua. La densidad del

agua es 1 g/cm^3 . Si solo la mitad del objeto se encuentra sumergido, el valor de la masa del agua desalojada por el objeto es de:
Physics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

Ver explicación

Explanation:

Según los principios de Arquímedes, el empuje hacia arriba de un objeto sumergido en un fluido es igual al peso del fluido desplazado.

Por eso

Empuje hacia arriba = volumen del objeto * densidad del fluido * aceleración debida a la gravedad

Empuje hacia arriba = 2 * 10 ^ -6 / 2 * 1 * 10 ^ 3 * 10

Empuje hacia arriba = 0.01 N

Desde;

Empuje hacia arriba = peso del fluido desplazado

peso del fluido desplazado = 0.01 N

Masa de fluido desplazado = 0.01 N / 10 = 1 * 10 ^ -3 Kg o 1 g

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sound sensor display reads 40 dB inside and outside it reads 80dB. how many times louder is it outside than inside?
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The difference is (80 dB - 40 dB) = 40 dB.

The sound is 40 dB louder outside.

Each 10 dB means 10 times more sound power.

40 dB louder means 10x10x10x10 times more sound power.

That's <em>10,000 times</em> more sound power outside than inside.

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harkovskaia [24]

0.56 A is the current of the secondary coil.

transformer is the device that transfer electric energy from one AC circuit to another.

we know that ;

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learn more about transformers-

brainly.com/question/26991007

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4 0
1 year ago
A crane raises a 12,000 N marble sculpture at a constant velocity onto a pedestal 1.5 m above the ground outside an art museum.
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For the work, applicate formula:

\boxed{\boxed{\green{\bf{W = F\times d}}}}

According our data:

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