Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.
where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
![P=1027*9.81*6.25\\P=62967.93[Pa]](https://tex.z-dn.net/?f=P%3D1027%2A9.81%2A6.25%5C%5CP%3D62967.93%5BPa%5D)
The net force is:
![F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]](https://tex.z-dn.net/?f=F%20%3D%20P%2AA%5C%5CF%20%3D%2062967.93%2A0.00849%5C%5CF%20%3D%20534.6%5BN%5D)
Answer:
The magnitude of the induced Emf is 
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the 
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V
Answer:
Base quantities are the minimum numbers of the physical quantities. Base quantities are defined as the physical quantities which can not be defined in terms of other physical quanities. There are seven base quantities. Physical Quantitie Units Derived Quantities are defined as those physical quantities which are derived from the base quantities.
Explanation:
A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit. A physical quantity possesses at least two characteristics in common, one is numerical magnitude and other is the unit in which it is measured.
Distinguish between a basic physical quantity and a derived physical quantity giving an example of each. Answers. Basic physical quantities are quantities which can be obtained without derivation. e.g Temperature. While derived physical quantities are quantities which can only be obtained from other physical quantities.
Answer:
a. a = 
b. T = -0.81 N
Explanation:
Given,
- weight of the lighter block =
- weight of the heavier block =
- inclination angle =
- coefficient of kinetic friction between the lighter block and the surface =
- coefficient of kinetic friction between the heavier block and the surface =
- friction force on the lighter block =
- friction force on the heavier block =
Let 'a' be the acceleration of the blocks and 'T' be the tension in the string.
From the f.b.d. of the lighter block,
From the f.b.d. of the heavier block,
From eqn (1) and (2), we get,
![\Rightarrow a\ =\ \dfrac{g(w_1sin\theta\ -\ \mu_1w_1cos\theta\ +\ w_2sin\theta\ +\ \mu_2w_2cos\theta)}{w_1\ +\ w_2}\\\Rightarrow a\ =\ \dfrac{g[sin\theta(w_1\ +\ w_2)\ +\ cos\theta(\mu_2w_2\ -\ \mu_1w_1)]}{w_1\ +\ w_2}\\](https://tex.z-dn.net/?f=%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7Bg%28w_1sin%5Ctheta%5C%20-%5C%20%5Cmu_1w_1cos%5Ctheta%5C%20%2B%5C%20w_2sin%5Ctheta%5C%20%2B%5C%20%5Cmu_2w_2cos%5Ctheta%29%7D%7Bw_1%5C%20%2B%5C%20w_2%7D%5C%5C%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7Bg%5Bsin%5Ctheta%28w_1%5C%20%2B%5C%20w_2%29%5C%20%2B%5C%20cos%5Ctheta%28%5Cmu_2w_2%5C%20-%5C%20%5Cmu_1w_1%29%5D%7D%7Bw_1%5C%20%2B%5C%20w_2%7D%5C%5C)
![\Rightarrow a\ =\ \dfrac{9.81\times [sin30^o\times (3.0\ +\ 7.0)\ +\ cos30^o\times (0.31\times 7.0\ -\ 0.13\times 3.0)]}{3.0\ +\ 7.0}\\\Rightarrow a\ =\ 6.4\ m/s.](https://tex.z-dn.net/?f=%5CRightarrow%20a%5C%20%3D%5C%20%5Cdfrac%7B9.81%5Ctimes%20%5Bsin30%5Eo%5Ctimes%20%283.0%5C%20%2B%5C%207.0%29%5C%20%2B%5C%20cos30%5Eo%5Ctimes%20%280.31%5Ctimes%207.0%5C%20-%5C%200.13%5Ctimes%203.0%29%5D%7D%7B3.0%5C%20%2B%5C%207.0%7D%5C%5C%5CRightarrow%20a%5C%20%3D%5C%206.4%5C%20m%2Fs.)
part (b)
From the eqn (2), we get,
