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Bas_tet [7]
3 years ago
12

.

Physics
1 answer:
Dmitrij [34]3 years ago
7 0
Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2

Substitute g=10m/s^2, t=5s, d=125m
You might be interested in
3. A car travels 800 miles in 6 hours. What was the car’s average speed? Be sure to include units in your answer
vredina [299]

Answer:

133.33 miles per hour

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained.

5 0
3 years ago
Select the correct answer. A ball is thrown straight down from the top of a building at a velocity of 16 ft/s. The building is 4
BartSMP [9]

Answer:

The ball takes 5s to reach the ground

Explanation:

in order to solve this problem we use the kinematics equation with gravity as acceleration:

h=v_0t+1/2*gt^2

we replace the values

0=1/2*32t^2+16t-480

We solve this quadratic equation:

t=5s

t=-6s   (this solution has not physical sense)

8 0
3 years ago
A 7.25 kg7.25 kg block is sent up a ramp inclined at an angle ????=28.5°θ=28.5° from the horizontal. It is given an initial velo
Free_Kalibri [48]

Answer:

15.03 m

Explanation:

Given:

mass of the block, m = 7.25 kg

Angle, Θ = 28.5°

Initial speed of the block, v₀ = 15 m/s

let the distance traveled by the block be 's'

Now, applying the work energy theorem,

we have

(m\times g\times\sin(\theta)\times s) + \mu_k\times mg\times s\times cos(\theta) = \frac{1}{2}\times m\times v^2

on substituting the values in the above equation, we get

(7.25\times 9.8\times\sin(28.5^o)\times s) + 0.326\times 7.25\times9.8\times s\times cos(28.5^o) = \frac{1}{2}\times 7.25\times 15^2

or

33.902\times s) +20.35\times s = 815.625

or

54.252\times s = 815.625

s = 15.03 m

Hence, the block will travel 15.03 m up the ramp

6 0
3 years ago
A jogger moves from a position x =
vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0
3 years ago
Suppose you wish to whirl a pail full of water in a vertical circle at a constant speed without spilling any of its contents (ev
Yanka [14]

Answer:

V = 2.87 m/s

Explanation:

The minimum speed required would be that at which the acceleration due to gravity is negated by the centrifugal force on the water.

Thus, we simply need to set the centripetal acceleration equal to gravity and solve for the speed V using the following equation:

Centripetal acceleration = V^2 / r

where r is the distance of water from the pivot or shoulder.

For our case, r will be 0.65 + 0.19 = 0.84 m

and solving the above equation we get:

9.81 = V^2 / 0.84

V^2 = 8.2404

V = 2.87 m/s

6 0
3 years ago
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