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3 years ago

(0 – 3) – 8 (2 + 4)

Mathematics

1 answer:

alisha [4.7K]3 years ago

6 0

Answer:

-51

Step-by-step explanation:

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Find the estimates of x^2-x-2=3

Julli [10]

Answer:

$x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79$

Step-by-step explanation:

Given

Quadratic equation is

$x^2-x-2=3\\x^2-x-5=0$

Roots of the quadratic equation $ax^2+bx+c=0$ are

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

So, for the given equation roots are

$x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79$

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3 years ago

How would yo expand ln (1/49k)?

dedylja [7]

Answer:

Step-by-step explanation:

It depends on whether you mean ln(1/49k) or ln(1/(49k)).

3 0

3 years ago

Identify the vertex and y-intercept of the graph of the function y = (x + 2) − 3. Use the drop-down menus to show your answer.

shepuryov [24]

Answer:

Was the function typed incorrectly? Should it be y = $(x + 2)^{2} - 3$ ?

Step-by-step explanation:

8 0

3 years ago

Hey! how's your Saturday going :) <br> (if it's Saturday for you)

Bad White [126]

Answer:

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I got this wrong. not sure where I went wrong

oksano4ka [1.4K]

Answer:

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

Step-by-step explanation:

Formula ………………………………………………………………………

The equation of a circle with center (a , b) and radius r is :

$\left( x-a\right)^{2} +\left( y-b\right)^{2} =r^{2}$

===================

Now ,let’s apply what we have learnt:

The equation of the circle with center (a , b) = (2 , 6) and radius r = 2√3 is :

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =\left( 2\sqrt{3} \right)^{2}$

$\Longleftrightarrow \left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

$\text{Note :} \left( 2\sqrt{3} \right)^{2} =2^{2}\times \sqrt{3}^{2} =4\times3=12$

7 0

2 years ago

(0 – 3) – 8 (2 + 4)​

(0 – 3) – 8 (2 + 4)