Solve by elimination. 2x – 1= 20<br> 2.x + 3y = 20

What is 3/8 as a decimal and percent?

vova2212 [387]

3/8 as a decimal equals=
3÷8=0.375

3/8 as percent equals=
0.375= 37.5%
:)

4 0

3 years ago

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The length of a rectangle is 11 less than 9 times the width. The

Olin [163]

Answer:

Length = 7 Width = 2

Step-by-step explanation:

L = Length

W = Width

L=9w-11

2L+2W=18

2(9W-11) + 2W = 18

18W - 22 +2W = 18

20W -22 = 18

20W = 40

W = 2

L = 9(2)-11

L=18-11

L=7

8 0

3 years ago

HELP ASAP 15 POINTS!!!<br> What is the solution to this equation?<br> 6(x-5)=4x+20

Andre45 [30]

Answer:

Step-by-step explanation:

What is the solution to this equation?

6 * (x - 5) = 4x + 20

6x - 30 = 4x + 20

2x = 20 + 30

2x = 50

x = 50 : 2

x = 25

-------------------

check

6 * ( 25 - 5) = 4 * 25 + 20

6 * 20 = 100 + 20

120 = 120

the answer is good

3 0

2 years ago

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In the diagram below, line AB and line CD intersect at point P. Name the angle that is always congruent to <APC

Alex Ar [27]

<dpb because they’re vertical angles (they’re directly across from each other)

5 0

3 years ago

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At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago

Solve by elimination. 2x – 1= 20 2.x + 3y = 20