Answer:
The answer is 1/3.
Step-by-step explanation:
A coin has either heads or tails. The odds of a coin getting heads is 1/2.
There are three equal-sized sections with numbers 3, 6 and 9 on the spinner. There are two sections with numbers greater than 3, which are 6 and 9. The odds of getting a number greater than 3 is 2/3.
To find the overall probability of both incidents occurring, the two fractions are multiplied together, which is 1/2 * 2/3 = 1/3
18
the calculated percentage of 75 anf 24 is 18
Negative 72.75 is your product. It is very simple once you understand it.
Answer:
A) The probability of picking a yellow ball from the bag is 26.66%.
B) The probability of picking a blue ball from the bag is 40%.
C) The probability of picking a yellow ball and then a blue ball is 11.42%.
Step-by-step explanation:
Since a bag contains 4 yellow balls, 5 red balls, and 6 blue balls, to determine what is the probability of picking a yellow ball from the bag, what is the probability of picking a blue ball from the bag and what is the probability of picking a yellow ball and then a blue ball after replacement, the following calculations must be performed:
A)
4 + 5 + 6 = 100
4 = X
15 = 100
4 = X
4 x 100/15 = X
400/15 = X
26.66 = X
Therefore, the probability of picking a yellow ball from the bag is 26.66%.
B)
15 = 100
6 = X
6 x 100/15 = X
600/15 = X
40 = X
Therefore, the probability of picking a blue ball from the bag is 40%.
C)
14 = 100
6 = X
6 x 100/14 = X
600/14 = X
42.85 = X
0.2666 x 0.4285 = X
0.1142 = X
Therefore, the probability of picking a yellow ball and then a blue ball is 11.42%.
550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
