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3 years ago

Which of the following equations is equivalent to y = lnx?

Mathematics

1 answer:

harkovskaia [24]3 years ago

4 0

Step-by-step explanation:

e^ln x - ln xy is equal to (a) y (b) 1/y (c) x (d) 1/x (e) none of these Which of the following equations is equivalent to the equation y = 5^x? (a) y = ln(5x) (b) y = e^5 ln x (c) y = e^x ln 5 (d) y = x ln 5 (e) none of these When $400 is invested in an account that earns 7.5% annualinterest, compounded quarterly, the accumulated value after 5 years (to the nearest cent) is (a) $581.99 (b) $579.98 (c) $574.25 (d) $550.00 (e) none of these

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ASAP please help with math thanks

fomenos

Answer:

2: 6,8

Step-by-step explanation:

2) Look at the range from 6-8 then look at the frequency. The frequency is the highest so that is the most frequent range that they scored in.

I apologise for only answering one question. I don't have access to paper rn and this is hard stuff to do in my head.

5 0

3 years ago

Find the generating function for the sequence 1,-2,4,-8, 16, ...

kirill [66]

Answer:

$a(x)=\dfrac{1}{1+2x}$

Step-by-step explanation:

The generating function a(x) produces a power series ...

$a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots$

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

$a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}$

This can be rearranged to ...

$a_n+2a_{n-1}=0$

We can formulate this in terms of a(x) as follows, then solve for a(x).

$\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}$

The generating function is ...

a(x) = 1/(1+2x)

3 0

3 years ago

Read 2 more answers

Funny memes.....................

scoundrel [369]

Answer:

haha funny lel he made a funny

4 0

3 years ago

Read 2 more answers

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa

arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

The question is incomplete:

The significance level is 0.05.

The data is:

Brand X: 91, 100, 88, 89

Brand Y: 99, 96, 94, 99

Brand Z: 83, 88, 89, 76

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

$H_0:\mu_x=\mu_y=\mu_z$

Alternative hypothesis: the means are not equal

$H_a: \mu_x\neq\mu_y\neq\mu_z$

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

$s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33$

Then, we calculate the mean standard error (MSE):

$MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78$

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

$M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91$

The MSB is then:

$s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172$