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3 years ago

if you had a block of each type of wood with the same dimensions,how would their weights compare?explain?

2 answers:

8 0

For this case we have the following equation:
Density = mass / volume
If the volume is the same, then the object with the greatest weight will be the one with the highest density.
You must know the type of way to know the value of the density.
Answer:
The weight of the blocks will depend on the density if the volume is the same.

expeople1 [14]3 years ago

8 0

If the dimensions of the wood are the same, then it means that they have the same volume.
The weight of an object is direct proportional to the volume but now the volume is constant.
So, if the blocks are from the same type of wood, then their weight will be the same.
If the blocks comes from different types of wood, then the weight would differ depending with the density of each type of wood. That is, if the wood is denser then it will weigh more than less dense wood.

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Join g••gle meet code -: tsh-zezg-dii

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3 years ago

If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=

Alexxx [7]

$\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
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\textit{now, the "y" in the inverse, is really just g(x)}
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\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\$

$\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
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1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}$

now, if we just knew what g(2) is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus 2 = 2x+sin(x)

$\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}$

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it

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2 years ago

1. According to New Jersey Transit, the 8:00 a.m. weekday train from Princeton to New York

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2 years ago

Nick can run the 440 yard dash in 55 seconds, and Jack can run it in 88 seconds. How great a handicap must Nick give Jack for th

Zepler [3.9K]

Jack --> 440 = rate * 88Jack --> 5 yrds/sex = rateJack in 55 seconds --> distance = 5 * 55 = 275 yrds440 - 275 = 165 yards handicap.

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3 years ago

Gabrielle's age is two times Mikhail's age. The sum of their ages is 81. What is Mikhail's age?

Darya [45]

Answer:

Step-by-step explanation:

Let g be Gabrielle's age and m be Mikhail's age.

We can turn the statements the problem gives us into mathematical expressions to help us solve.

Gabrielle's age is two times Mikhail's age:

g = 2m

The sum of their ages is 81:

g + m = 81

This gives us a system of equations that will allow us to solve for Gabrielle's age.

g + m = 81

(2m) + m = 81

3m = 81

m = $\frac{81}{3}$

m = 27

If we need to solve for Gabrielle's age, we can do the following.

g = 2m

2(27) = g

54 = g

g = 54

Mikhail's age is 27.

Gabrielle's age is 54.

8 0

2 years ago

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