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2 years ago

15

436÷2??? Con paso a paso no entendí y cuáles son los números paresjnbhhvygctfctgcgtvyg ygvybyhhvhvyvgyvchvgvgvgvgvgvggvgvggvygbb

hvvvyhhcvuvyhv te fxftgvyy

1 answer:

belka [17]2 years ago

7 0

Answer:

218

Step-by-step explanation:

436 ÷ 2

Using long division

436/2

4 ÷ 2 = 2

3 ÷ 2 = 1 remainder 1

We combine 1 and 6 together to give us 16

16 ÷ 2 = 8

Therefore, 436 ÷ 2 = 218

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Prove that tan60+tan70-tan50+tan10=2sqrt3?

LiRa [457]

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<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>

<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>

<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>

<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>

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3 years ago

The surface area of a melting snowball decreases at a rate of3.8cm2/min. Find the rate at which its diameter decreases when the

Scorpion4ik [409]

Answer:

Step-by-step explanation:

This is a pretty basic related rates problem. I'm going to go through this just like I do in class when I'm teaching it to my students.

We see we have a snowball, which is a sphere. We are talking about the surface area of this sphere which has a formula of

$S=4\pi r^2$

In the problem we are given diameter, not radius. What we know about the relationship between a radius and a diameter is that

d = 2r so

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$S=4\pi(\frac{d}{2})^2$ which simplifies to

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$S=\pi d^2$ (the 4's cancel out by division). Now that is a simple equation for which we have to find the derivative with respect to time.

$\frac{dS}{dt}=\pi*2d\frac{dD}{dt}$ Now let's look at the problem and see what we are given as far as information.

The rate at which the surface area changes is -3.8, and we are looking for $\frac{dD}{dt}$ , the rate at which the diameter is changing, when the diameter is 13. Filling in:

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Answer:

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Step-by-step explanation:

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-E :)

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