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3 years ago

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True or false: In order to fill this figure with unit cubes, you would need to fill in 7 cubes in length, 10 cubes in height, an

d 3 cubes in width. Then, you would fill the rest of the space with cubes.

2 answers:

Naddik [55]3 years ago

8 0

The answer to this is true

Anit [1.1K]3 years ago

5 0

The answer is true.

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What is the answer for -8n=13

KatRina [158]

Answer:

-13/8

Step-by-step explanation:

u divied by -8 to get n by itself

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2 years ago

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Hannah travels 6 times as many minutes to work as Raoul does. Together, they travel for 63 minutes. How many minutes does Hannah

Anna71 [15]

The equation would be 6x+x=63. Not sure how the models play out, but good luck

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3 years ago

Need help I don’t understand new topic answers please

goblinko [34]

1) c= 3.5cm × 22/7

c= 77cm/7 = 11cm

2) c= 2×3.14×5cm

= 6.28× 5cm

=31.4cm

3) L=180/360 × 22/7 × 3cm

= 1/2 × 22/7 ×3cm

=4.71 cm

4) c=12cm ×3.14

=37.68cm

5) c = 4.5cm × 3.14

=14.13cm

6) c = 6.7cm × 3.14

= 21.038cm

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2 years ago

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frozen [14]

The height is 22 inches? It says it in the question

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3 years ago

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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago