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3 years ago

Find the equation of the line through point (3,2) and perpendicular to 3x + 5y = 15

Mathematics

1 answer:

Vesnalui [34]3 years ago

6 0

Answer:

y=5/3x-3

Step-by-step explanation:

first, let's put 3x+5y=15 into y=mx+b form

move 3x to the other side

5y=-3x+15

divide by 5

y=-3/5x+3

now, perendicular lines have slopes that are negative and reciprocal.

With our new equation we can automatically find the slope, which would be 5/3.

now, we need to find b

plug the points (3,2) into y=5/3x+b

2=5/3(3)+b

2=5+b

-3=b

so that means that our equation will now be

y=5/3x-3.

Hope this helps!

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Please help. Thank you

Inessa [10]

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

6 0

3 years ago

Help please! I’m giving brainliest to however gets this question right.

Arisa [49]

Answer:

They both have area 4

Step-by-step explanation:

Area of the square:

$base*height = 2 * 2 = 4$

Area of the triangle:

Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:

$\frac{1}{2}base*height$

$\frac{1}{2}4\sqrt2*\sqrt2=4$

We know the length of the diagonal is $\sqrt2$ as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.