Hey there! :)
To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.
Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept
Since we're already given the slope, all we really need to do is find the y-intercept.
We can do this by plugging our known values into the slope-intercept equation.
y = mx + b
Since we're trying to find "b," we need to plug in "y, m, x" into our formula.
(1) = (2)(5) + b
Simplify.
1 = 10 + b
Subtract 10 from both sides.
1 - 10 = b
Simplify.
-9 = b
So, our y-intercept is 9!
Now, we can very simply plug our known values into slope-intercept form.
y = mx + b
y = 2x - 9 → final answer
~Hope I helped!~
Answer:
-1.70588235294
1. X3, 15x - 10y = 80 15x - 7y = 51
-17y = 29
2. 8 = 1/60 + a. 8 - 1/60 = 7.98333333333
6 = 1/80 + b. 6 - 1/80 = 5.9875
13.9708333333
3. I genuinely dont know sorry.
4. Pencil = $0.05. Pen = $1.05
Step-by-step explanation:
Please- Parenthesis
Excuse -Exponets
My - Multiplication
dear- Division
aunt- Addition
sally- Subtraction
This is easy just find out what 5^2 equals which will be 5x5=25 (when dealing with a squared number you will always times it by itself. so if you had 10^2 it would be 100.) so now that we know 5^2 is 25 we then can add the 20 which gets 25+20=45! Hope this helps!