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Fudgin [204]
3 years ago
14

Which statements about a rhombus are always true? Its diagonals bisect each other. All 4 angles are 90°. Its diagonals are congr

uent. Its diagonals are ⊥ to each other.
Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0
Hello,


The answer is Its diagonals are congruent. Its diagonals are ⊥ to each other.


I believe you can pick more than 1.

Hope this helps
Delicious77 [7]3 years ago
3 0

Answer:

(C) and (D)

Step-by-step explanation:

From the properties of rhombus, we know that the diagonals are always congruent and the diagonals are perpendicular to each other.

Thus, only options (C) and (D) are correct as rest of the two options are not true regarding the properties of rhombus.

Hence, option C and D are true about rhombus.

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PLEASE HELP ME NOW URGENT
timama [110]

ANSWER

y   = 3 \pm \sqrt{21}

EXPLANATION

The quadratic equation is:

{y}^{2}  - 6y - 12 = 0

Group variable terms:

{y}^{2}  - 6y = 12

Add the square of half, the coefficient of y to both sides.

{y}^{2}  - 6y  + ( - 3) ^{2} = 12 + ( - 3) ^{2}

{y}^{2}  - 6y  + 9= 12 + 9

The LHS us now a perfect square trinomial:

{(y - 3)}^{2}= 21

Take square root:

y - 3 =  \pm \sqrt{21}

y = 3 \pm \sqrt{21}

The first choice is correct.

8 0
3 years ago
Read 2 more answers
If 12 +22+ 32 +
kakasveta [241]

Answer:

m2

Step-by-step explanation:

the 2nd equation is double the first one and the first one is 1

8 0
2 years ago
Extension question (provide a full explanation of your method(s):
Volgvan

Answer:

Ann has little chance to win if she is presented with 4 counters.

Ann can always win from a pile of 6 counters.

(both are explained below)

Step-by-step explanation:

If Ann  is presented with 4 counters, and

1. if she takes out 3, she will lose since the opponent will  pull out 1 and the last one.

2. if she takes 2 her opponent will take out 1 and she can't pull out the last 1 since her opponents last move was to pull out 1  counter so she will lose.

3. If she takes out 1 and her opponent takes out 3 in the next move she loses.

but if instead of 3 her opponent takes out 2 and in the last move Ann takes out the last 1  then she will win.

So, If Ann is presented with 4 counters she has little chance to win provided in the move just before, her opponent didn't move 1 counter.

Now,

if there is 6 counters to Ann, and

1., if Ben's  previous move was 1 then Ann can win if she takes out 3 or 2.

If she takes out 3 Ben can take out 1 or 2 and in the last move she will take out 2 or 1 (respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

2. if Ben's  previous move was 2 then Ann can win if she takes out 1 or 3.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 3 Ben can  take out 1 or 2 and in the last move Ann wins by pulling out 2 or 1 respectively.

2. if Ben's  previous move was 3 then Ann can win if she takes out 1 or 2.

If she takes out 1 Ben can take out 2 or 3 and in the last move she will take out 3 or 2(respectively) and winning the game.

If she takes out 2 Ben can  take out 1 or 3 and in the last move Ann wins by pulling out 3 or 1 respectively.

 

 

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=13%20-%204%20%5Ctimes%205%20%5Cdiv%202%20%2B%2010%20%3D%20%20%5C%5C%20" id="TexFormula1" title
const2013 [10]

Answer:

So, 13 - 20 ÷2 + 10 = 13 - 10 + 10 = 3 + 10 = 13 ;

Step-by-step explanation:


3 0
3 years ago
A rectangle measures 8/3 inches by 9/4 inches. What is its area?
GREYUIT [131]

Answer:

To find the area, you have to multiply the length times the width

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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