Answer:
D
Step-by-step explanation:
Step-by-step explanation:
Frequency of a mass-spring system is:
f = √(k/m) / (2π)
Given f = 2/π Hz and m = 20 kg:
2/π Hz = √(k / 20 kg) / (2π)
4 Hz = √(k / 20 kg)
16 s⁻² = k / 20 kg
k = 320 kg/s²
k = 320 N/m
If the 20 kg mass is replaced with an 80 kg mass, the frequency is:
f = √(320 kg/s² / 80 kg) / (2π)
f = √(4 s⁻²) / (2π)
f = 2 Hz / (2π)
f = 1/π Hz
Answer: Third option.
Step-by-step explanation:
To solve this exercise it is important to remember the following:
1) By definition, equivalent expression have the same value, but they look different.
2) The multiplication of signs:

Then, given the following expression provided in the exercise:

You need to distribute the postive sign:

And finally, you must add the like terms:

As you can notice, the expression obtained matches with the expression shown in the third option.
Step-by-step explanation:
84+36=120ans..........