Im doing this question rn and I believe the answer should be C) the ratio of the student body that are in 12th grade and play two or more sports.
Step-by-step explanation: I chose this bc there are 28 12th graders that play 2 or more sports and the total student body is 612. So 28/612 makes most sense to me. Sorry this is so late but I just checked and it’s right!
Answer:
<em>71.6 degrees </em>
Step-by-step explanation:
The formula for calculating the angle between two vectors is expressed as;
u.v = |u||v|cos theta
u.v = (8, 4).(9, -9)
u.v = 8(9)+4(-9)
u.v = 72-36
u.v = 36
|u| = √8²+4²
|u| = √64+16
|u| = √80
|v| = √9²+(-9)²
|v| = √81+81
|v| = √162
36 = √80*√162 cos theta
36 = √12960 cos theta
36 = 113.84 cos theta
cos theta = 36/113.84
cos theta = 36/113.84
cos theta = 0.3162
theta = arccos (0.3162)
<em>theta = 71.6 degrees </em>
<em>Hence the angle between the given vectors is 71.6 degrees </em>
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Answer:
b
Step-by-step explanation:
In a 30-60-90 right triangle, the hypotenuse is twice the length of the short leg.
The hypotenuse is AB and is 18.
The short leg is BC and is 9.
The only choice with BC = 9 is b.
Answer: b
Answer:
x=126
Step-by-step explanation:
