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Mariana [72]
3 years ago
14

Given quadrilateral ABCD, where the diagonals AC and BD intersect at point E. AE⎯⎯⎯⎯⎯⎯⎯≅EC⎯⎯⎯⎯⎯⎯⎯⎯AE¯≅EC¯ and BE⎯⎯⎯⎯⎯⎯⎯≅DE⎯⎯⎯⎯⎯⎯

⎯⎯BE¯≅DE¯. Can you prove can you prove that the figure is a parallelogram? Explain.
Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Given:

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

AE\cong EC

BE\cong DE

To prove:

The figure is a parallelogram.

Solution:

We know that if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

AE\cong EC

BE\cong DE

Since the diagonals AC and BD of a quadrilateral ABCD bisect each other, therefore the quadrilateral ABCD is a parallelogram.

Hence proved.

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atroni [7]

Answer:

A. x = 13

y = (13√3)/3

Step-by-step explanation:

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Cross multiply

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Sin 30 = y*3/(26√3)

½ = 3y/(26√3) (sin 30 = ½)

Cross multiply

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5 0
3 years ago
Phyllis invested $10,500 a portion earning a simple interest rate of 9(1/5)% per year and the rest earning a rate of 9% per year
Alenkinab [10]
Total investment  = $10,500

Let x = amount of first investment, and y the amount of the second investment.

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Second investment:
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Total interest after one year is $957.00, therefore
0.092x + 0.09y = 957       
 or
1.0222x + y = 10633.33   (1)

Also,
x + y = 10500               (2)

Subtract (2) from (1).
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Answer:
The first investment is $6,000 at 9 (1/5)% rate;
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For questions 7 - 12, solve the problem, expressing your answer using the correct number of
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