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Mariana [72]
3 years ago
14

Given quadrilateral ABCD, where the diagonals AC and BD intersect at point E. AE⎯⎯⎯⎯⎯⎯⎯≅EC⎯⎯⎯⎯⎯⎯⎯⎯AE¯≅EC¯ and BE⎯⎯⎯⎯⎯⎯⎯≅DE⎯⎯⎯⎯⎯⎯

⎯⎯BE¯≅DE¯. Can you prove can you prove that the figure is a parallelogram? Explain.
Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Given:

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

AE\cong EC

BE\cong DE

To prove:

The figure is a parallelogram.

Solution:

We know that if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

AE\cong EC

BE\cong DE

Since the diagonals AC and BD of a quadrilateral ABCD bisect each other, therefore the quadrilateral ABCD is a parallelogram.

Hence proved.

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uysha [10]

Answer:

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Step-by-step explanation:

Hypotenuse is 10 because it is the opposite of the right angle

8^2+x^2=10^2

64+x^2=100

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Jake works at a fast food restaurant last week he worked 25 hours and earned 210.75 what is jakes hourly pay
umka2103 [35]

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7 0
3 years ago
The trinomial 2x2 + 13x + 6 has a linear factor of x + 6. 2x2 + 13x + 6 = (x + 6)(?) What is the other linear factor? x + 3 x +
BartSMP [9]
Answer: 2x+1

Notice how the 2x in the answer and the x, from x+6, multiplies to 2x^2
Also the 1 from the answer and the 6 from x+6 multiplies to 6
The results of 2x^2 and 6 are the first and last terms respectively of the original trinomial. None of the other answer choices fit this.

You can use the FOIL or box method to get
(x+6)*(2x+1) = x*(2x+1)+6*(2x+1)
(x+6)*(2x+1) = 2x^2+x+12x+6
(x+6)*(2x+1) = 2x^2+13x+6
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5 0
3 years ago
Read 2 more answers
See attachment to help
Anton [14]
Average rate of change [1,3] = (15.882 - 11.38)/(3-1) = 4.502 /2 = 2.251


average rate of change [-4,-2] = (0.0971- 0.0018)/(-2+4) = 0.0953 /2 = 0.04765

average rate of change [1,3]  / average rate of change [-4,-2] 
= 2.251 / 0.04765
= 47.24

answer
47.24
8 0
3 years ago
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