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inysia [295]
3 years ago
12

Help please need done asap

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Answer is J

Step-by-step explanation:

Find one point: (1,0)

Substitute the numbers in the equations.

0+6= 3(1+1)

6= 3(2)

6=6

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One number is 6 times a first number. a third number is 100 times than the first number. If the sum of the three numbers is 784
sesenic [268]
It would be any number times 0 so yeah I hope this helps
5 0
3 years ago
Order the numbers from least to greatest 15, 20, -13, -20, -9, 7
Karo-lina-s [1.5K]
-20, -13, -9, 7, 13, 20
5 0
3 years ago
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Please help thank u.
Sever21 [200]

Answer:

-4, 3 1/2 JFURE8EGNRODG RE NEJEUSUEHEUE I did this for 20 characters

4 0
3 years ago
Hilda was simplifying some numerical expressions and made each of the following sequences of calculations. Name the mathematical
Galina-37 [17]

Answer:

Problem 1:

5 · (−4/3) · (2/5)

= (−4/3) · 5 · (2/5)   <em>Conmutative Property of Multiplication</em>

= (−4/3) · (5 · (2/5))  <em>Associative Property of Multiplication</em>

= (−4/3) · (2/1) = −8/3 = −2*2/3<em> Multiplied fractions and extracted common factor</em>

Problem 2:

17 + 29 + 3+ 1

= 17 + 3 + 29 + 1  <em>Conmutative Property of Addition</em>

= (17 + 3) + (29 + 1)  <em>Associative Property of Addition</em>

= 20 + 30 Added groups

= 50 Added terms

Step-by-step explanation:

<u>For the Problem 1:</u>

In the first step, Hilda applied the <em>Conmutative Property of Multiplication</em>, because she changed the order of the numbers in the product

In the second step, she applied the <em>Associative Property of Multiplication, </em>because she agrouped the product of 5 and<em> </em>2/5 to perform it sepparately

In the third step, she calculated<em> the product of the fractions</em> -4/3 and 2/1, then she extracted 2 as a <em>common factor</em> to express the fraction as -2*2/3

<u>For the Problem 2:</u>

In the first step, Hilda applied the <em>Conmutative Property of Addition, </em>because she changed the order of the numbers in the sum

In the second step, she applied the<em> Associative Property of Addition, </em>because she associated the addition of 17 and 3 and the addition of 29 and 1, to calculate them in groups.

<em />

4 0
3 years ago
Read 2 more answers
Find the iqr of 4 5 6 8 9 10 11 12
77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.



3 0
3 years ago
Read 2 more answers
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