Answer:
Unbounded, infinite number of solutions
Step-by-step explanation:
1. Graph each inequality separately
2. Choose test point to determine which side of line needs to be shaded
3. The solution will be the the area where the shadings from both inequalities overlap
Since, the overlap almost covers the 2nd and 3rd quadrants there are an infintite number of solutions
Answer:
- circumference: 12.56 yd
- area: 12.56 yd²
Step-by-step explanation:
The formula for circumference is ...
C = πd
C = (3.14)(4 yd) = 12.56 yd . . . . . . . . fill in the numbers; do the arithmetic
The circumference is 12.56 yd.
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Since the diameter is 4 yd, the radius is half that, or 2 yd. The formula for the area is ...
A = πr²
Fill in the numbers and do the arithmetic.
A = (3.14)(2 yd)² = 12.56 yd²
The area is 12.56 yd².
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<em>Comment on units</em>
In problems such as these, I find it is often useful to keep the units with the numbers. The units can be treated like any variable: multiplied, divided, measures combined by addition or subtraction of "like units".
Just as (2a)² = 2²·a² = 4a², so does (2 yd)² = 2²·yd² = 4 yd². You can be sure that if the units of the problem don't make sense, there is an error somewhere.
Multiple 6 with numbers inside paranthesis:
12x - 66 + 15 = 21
add 66 fhen substrack 15 from both sides :
12x = 72 divide both sides with 12:
x = 6
