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Misha Larkins [42]
2 years ago
13

У — 3x 4 у > 4х +1 Anyone know the answe on how to solve this???

Mathematics
1 answer:
Katen [24]2 years ago
8 0

Answer:

Unbounded, infinite number of solutions

Step-by-step explanation:

1. Graph each inequality separately

2. Choose test point to determine which side of line needs to be shaded

3. The solution will be the the area where the shadings from both inequalities overlap

Since, the overlap almost covers the 2nd and 3rd quadrants there are an infintite number of solutions

You might be interested in
Help me pleaseee!!<br> Would appreciate ^^<br> **BRAINLIST, thanks and points***
sergey [27]

Answer:

See below

Step-by-step explanation:

22. 30 = 2 * 3 * 5

23. 126 = 2 * 3 * 3 * 7

24. 4900 = 2 * 2 * 5 * 5 * 7 * 7

25. 39204 = 2 * 2 * 3 * 3 * 3 * 3 * 11 * 11

26. There's no square number

27. The highest common factor are

   30 is 5

   126 is 7

  4900 is 7

 39204 is 11

28. The lowest common factor are

 30 is 2

 126 is 2

 4900 is 2

 39204 is 2

What about you? What did you get?

4 0
3 years ago
Anyone know how to do these?
Allushta [10]

Answer:

1.4x10^-7

Step-by-step explanation:

For Problem 6

First we would divide the first numbers together so 7.84 / 5.6 = 1.4

We then would add the exponenites together so -3+-4=-7

Leading our awnser to be 1.4x10^-7

6 0
3 years ago
PLEASE ANSWER I REALLY NEED IT I WILL GIVE 25 POINTS
jonny [76]

Answer:

I don´t know fully but you add by ones on top and add by threes on the bottom

Step-by-step explanation:

3 0
2 years ago
Solve y + -7 = 13 ?
ratelena [41]
Well first off if you have a negative sign in front of the seven, DO NOT have a plus sign because it will be confusing. So y-7=13? , You add 7 to 13 and = 20, so y= 20
3 0
3 years ago
Use the rule to write the first five terms of the pattern . rule :add 8, subtract 4. first term :13
Gnesinka [82]
1. 17  
2. 21
3. 25
4. 29
5. 33
Just take the 13, then add 8, then subtract 4, then with what you got keep going on to the next term.
3 0
3 years ago
Read 2 more answers
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