PROBLEM ONE
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Solving for x in 2x + 5y > -1.
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Step 1 ) Subtract 5y from both sides.
2x + 5y > -1
2x + 5y - 5y > -1 - 5y
2x > -1 - 5y
Step 2 ) Divide both sides by 2.
2x > -1 - 5y
So, the solution for x in 2x + 5y > -1 is...
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Solving for y in 2x + 5y > -1.
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Step 1 ) Subtract 2x from both sides.
2x + 5y > -1
2x - 2x + 5y > -1 - 2x
5y > -1 - 1x
Step 2 ) Divide both sides by 5.
5y > -1 - 1x
So, the solution for y in 2x + 5y > -1 is...
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PROBLEM TWO
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Solving for x in 4x - 3 < -3.
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Step 1 ) Subtract 3 from both sides.
4x - 3 < -3
4x -3 - 3 < -3 - 3
4x < 0
Step 2 ) Divide both sides by x.
4x < 0
x < 0
So, the solution for x in 4x - 3 < -3 is...
x < 0
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- <em>Marlon Nunez</em>
I believe the answer to 1/7 times 20 would be 2.9 that is rounded to the nearest tenth but if your rounding to the nearest whole number it would be 3
As for 1/9 of 82 it would be 9.1 rounded to the nearest tenth and it would be 9 rounded to the nearest whole number.
Answer:
x = -1, y = -4
Step-by-step explanation:
Let's solve our system of equations by substitution.
y = 5x + 9y = −x + 3
Step: Solve = 5x + 9 for y:
y = 5x + 9
Step: Substitute 5x + 9 for y in y = −x + 3:
y = −x + 3
5x + 9 = −x + 3
5x + 9 + x = −x + 3 + x (Add x to both sides)
6x + 9 = 3
6x + 9 + −9 = 3 + −9 (Add -9 to both sides)
6x = −6
6x/ 6 = −6/6(Divide both sides by 6)
x = −1
Step: Substitute −1 for x in y = 5x + 9:
y = 5x + 9
y = (5)(−1) + 9
y = 4(Simplify both sides of the equation)
So our answers are y = -4 and x = -1.
X=5
90°-50°=40°
5x+15=40°
5x=25°
x=5
P + 10 = 20 Subtract 10 from both sides
P = 10
Substitute P = 10 into P + Q = 16
P + Q = 16 Plug in 10 for P
10 + Q = 16 Subtract 10 from both sides
Q = 6
