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2 years ago

Solve 6!pls I need help!!

1 answer:

8 0

Answer:

deep nutz are for you only

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azamat

Have a nice day/night <3

4 0

2 years ago

inessss [21]

D is the answer. Hope this helps!

7 0

3 years ago

kherson [118]

Answer:

$sinA=\frac{opposite}{hypotenuse}$

Step-by-step explanation:

Soh-cah-toa is a great way to remember:

$sin=\frac{opposite}{hypotenuse}\\ cin=\frac{adjacent}{hypotenuse}\\ tan=\frac{opposite}{adjacent}$

You just remember the first letters : sine= opposite/hypotenuse , for example.

6 0

3 years ago

UkoKoshka [18]

Yes, it is a function

4 0

2 years ago

ryzh [129]

Anwnser:

1...3

Step-by-step explanation:

i dont know how to explain Hope it helps

7 0

3 years ago

Solve 6!pls I need help!!​