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ollegr [7]
3 years ago
6

Subtract: (3x- 7x² + 2) – (4x2 - 5 + 6X)

Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

−7(x−-143− 65)(x− 4/65+3)

Step-by-step explanation:

i  hope its right

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Which is the equation of a line that has a slope of 5 and passes through point (2, -3)?
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The answer is C y=1/2x+2
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How many ways can you purchase 3 CDs if there are 3 to choose from, 4 cassettes if there are 7 to choose from, and 2 DVDs if the
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<span>3C3 X 7C4 X 4C2 = 210 </span>
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How many inflection point(s) do you see ?
dimulka [17.4K]

Answer:

  7

Step-by-step explanation:

There is a point of inflection at each point where the graph crosses the line y=2. There are 7 points of inflection shown.

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A point of inflection is where the graph changes from being concave downward to concave upward, or vice versa. For a sine function, that is everywhere the function crosses its midline.

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PLEASE HELP
rusak2 [61]
C' ( 4, -2 )

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2 years ago
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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts
DochEvi [55]

Answer:

We accept  H₀   with the information we have, we can say level of ozone is under the major limit

Step-by-step explanation:

Normal Distribution

population mean  =   μ₀   =  7.5   ppm

Sample size     n   =  16      df  =  n  -  1  df  =  15

Sample mean      =    μ   =  7.8  ppm

Sample standard deviation   =  s  =  0.8

We want to find out if ozono level, is above normal level that is bigger than 7.5

1.- Hypothesis Test

null hypothesis                          H₀         μ₀   =  7.5

alternative hypothesis             Hₐ          μ₀  >  7.5  

2.-Significance level    α  =  0.01   we will develop one tail-test (right)

then   for   df  =  15    and    α =  0,01   from t -student table we get

t(c)  = 2.624

3.-Compute  t(s)

t(s)  =  (  μ -  μ₀ ) / s /√n            ⇒   t(s)  = ( 7.8  -  7.5 )*4/0.8

t(s)  = 0.3*4/0.8

t(s)  = 1.5

4.-Compare   t(s)   and  t(c)

t(s)  <  t(c)       1.5  <  2.64

Then  t(s) is inside the acceptance region. We accept  H₀

7 0
3 years ago
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