Answer: B is correct. Triangle PRS can be proven equilateral, and the hexagon is equilateral.
Step-by-step explanation: We can't see the theorem she applied however
From the construction, we can see that the arcs are drawn properly to construct an equilateral hexagon, and the component triangles are all equilateral
Answer:
See below ~
Step-by-step explanation:
Given :
<u>QRSTU ~ FGCDE</u>
Finding the scale factor :
- Take two corresponding sides in proportion
- RS : GC
- 40 : 12
- <u>10 : 3</u>
Applying the scale factor to find the missing sides :
- FG :
- QR : FG = 10 : 3
- 30/FG = 10/3
- FG = 30/10 x 3
- FG = 3 x 3
- <u>FG = 9</u>
- CD :
- ST : CD = 10 : 3
- 40/CD = 10/3
- CD = 40/10 x 3
- CD = 4 x 3
- <u>CD = 12</u>
- EF :
- UQ : EF = 10 : 3
- 30/EF = 10/3
- EF = 30/10 x 3
- EF = 3 x 3
- <u>EF = 9</u>
Answer:
at least a couple
Step-by-step explanation:
she should probably buy some more
I think the answer is C because AB is not a transversal
