Ask question

Ask question

All categories

4 years ago

5

Anjali went to Citizens Bank and borrowed $7,000 at a rate of 8%. The date of the loan was September 20. Anjali hoped to repay t

he loan on January 20. Assuming the loan is based on ordinary interest, Anjali will pay back how much interest on January 20?

1 answer:

olga_2 [115]4 years ago

4 0

Anjali will pay $93.54 in interest.

You might be interested in

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.

tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: $\frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3}$ square units

(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

$altitude=\frac{\sqrt{3}}{2}*side$

$side = \frac{36}{\sqrt{3}}$

Hence, area of the hexagon will be: $648\sqrt{3}$ square units

(24)

Given is the inradius of an equilateral triangle.

$Inradius = \frac{\sqrt{3}}{6}*side$

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = $\frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3}$ square units

4 0

3 years ago

Let A = {1,2,3,..., 8, 9, 10} B = {4, 7, 10}

Dovator [93]

The answers to the questions are

(i) B - A = Ф / null set

(ii) A - B = {1, 2, 3, 5, 6, 8, 9}

(iii) (A - B) ∩ (B - A) = Ф / null set

(iv) (A - B) ∪ (B - A) = {1, 2, 3, 5, 6, 8, 9}

A set contains different elements which are mathematical objects of any kind such as numbers, points, spaces, lines e.t.c.

Different types of set are -singleton setsfinite and infinite setsempty or null sets equal sets unequal sets equivalent sets overlapping sets disjoint sets subsets super sets power sets universal sets

According to question,

i ] B - A = 0/null set

ii ] A - B = [ 1,2,3,5,6,8,9 ]

iii ] (A-B) n (B-A) = 0/ null set

iv ] (A-B) u ( B-A) = [ 1,2,3,5,6,8,9 ]

Hence, the answers to the questions are

(i) B - A = Ф / null set

(ii) A - B = {1, 2, 3, 5, 6, 8, 9}

(iii) (A - B) ∩ (B - A) = Ф / null set

(iv) (A - B) ∪ (B - A) = {1, 2, 3, 5, 6, 8, 9}

To understand more about Set Theory refer - brainly.com/question/13458417#SPJ9

4 0

2 years ago

Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,

Kryger [21]

Answer:

$E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}$

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value $x \in (0,1)$ we want this:

$max(U_1, ....,U_n) \leq x$

And we can express this like that:

$u_i \leq x$ for each possible i

We assume that the random variable $u_i$ are independent and $P)U_i \leq x) =x$ from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

$P(X \leq x) = P(U_1 \leq 1, ...., U_n \leq x) \prod P(U_i \leq x) =\prod x = x^n$

And then cumulative distribution would be expressed like this:

$0, x \leq 0$

$x^n, x \in (0,1)$

$1, x \geq 1$

For each value $x\in (0,1)$ we can find the dendity function like this:

$f_X (x) = \frac{d}{dx} F_X (x) = nx^{n-1}$

So then we have the pdf defined, and given by:

$f_X (x) = n x^{n-1} , x \in (0,1)$ and 0 for other case

And now we can find the expected value for the random variable X like this:

$E(X) =\int_{0}^1 s f_X (x) dx = \int_{0}^1 x n x^{n-1}$

$E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}$

6 0

3 years ago

A notha wun ........

geniusboy [140]

Slope is -1/5

Y-intercept is 21

Equation is y=-1/5x+21

Yes it’s proportional :)

5 0

3 years ago

Read 2 more answers

X÷79 + 72 - 18 hellppppp

tino4ka555 [31]

Answer:

1/5688x-18

I am not sure about my answer because I think the question is missing some information but my answer is 1/5688x-18. Thanks!

7 0

3 years ago