Answer:
no habla español
Step-by-step explanation:
Check the picture below.
we know that AL is an angle bisector, so the angle at A gets cuts into two equal halves, we also know the angle at B is 30°, so the triangle ABC is really a 30-60-90 triangle, meaning the angle at A is really a 60° angle, cut in two halves gives us 30° and 30° as you see in the picture.
if the angles at A and B, inside the triangle ABL, are equal, twin angles are only made in an isosceles by twin sides, that means that AL = BL.
Looking at the triangle ALC, we can see is also another 30-60-90 triangle, and we can just use the 30-60-90 rule to get x=CL.
Answer: 0.0241
Step-by-step explanation:
This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where:
n = number of sampled variable which in this case = 21
r = variable outcome being determined which in this case = 5
p = probability of success of the variable which in this case = 0.31
q= 1- p = 1 - 0.31 = 0.69
P(X=5) = 21C5 × 0.31^5 × 0.69^16
P(X=5) = 0.0241
Answer:
EF , HG , Parallel
Step-by-step explanation:
Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.
Also given that AB was parallel to DC.
Now we have to fill in the certain blanks.
Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.
Also HG is parallel to DC, EFGH is a translated image of ABCD.
Also we are given that AB is parallel to DC. Hence we have following results.
AB║DC
AB║EF
Hence CD║EF
also
CD ║HG
CD║EF
Hence we can come to conclusion that
EF║HG
Hence our answer will be
corresponding segments EF and HG are parallel to each other.
