The minimum initial deposit Arthur must make is $ 4.24.
Since Arthur is saving money to buy a used car in 8 months, and the car costs $ 2,180, and Arthur plans to start with an initial deposit and then deposit 25% more than the previous month until he has enough money to buy the car, to determine what is the minimum initial deposit Arthur must make the following calculation should be performed:
- X x 1.25 x 1.56 x 1.95 x 2.44 x 3.05 x 3.81 x 4.76 = 2180
- 514.10X = 2180
- X = 2180 / 514.10
- X = 4.24
Therefore, the minimum initial deposit Arthur must make is $ 4.24.
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Answer:
1 solution
Step-by-step explanation:
Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...
-3x -3 +3x = -3x +3 +3
We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.
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In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)
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<em>Additional comment</em>
If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.
Your expected value is -$0.62.
We multiply the probability of winning by the amount won. There are 12 face cards out of 52 cards, and the amount won is 4:
12/52(4)
We also multiply the probability of losing by the amount lost. There are 40 cards that are not face cards out of 52, and the amount lost is 2:
40(52)(-2)
Adding these, we have:
(12/52)(4)-(40/52)(2) = -0.62.
The answer is the last one with Amir as the 5 is the extra, and the 3 is multiplied by x or in this case days, and it is at least not equal.
Answer:
2/6
1/6
2/6
0/6
Step-by-step explanation:
