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allsm [11]
3 years ago
5

Someone help me with this question ASAP and show work please and thank you

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

g(f(x)) = x

Step-by-step explanation:

You are given f(x) = -4x - 1 and g(x) = \frac{x+1}{-4}. Keep in mind that f(x) or g(x) is the same as a y = equation, but two separate equations.

You are trying to find g(f(x)), which means that you will use f(x) and substitute this value into the x value in the equation of g(x).

It will look like: g(-4x - 1) = \frac{x+1}{-4}

\frac{(-4x-1)+1}{-4}

Now evaluate the expression to solve the problem. Start by combining like terms.

\frac{(-4x)}{-4}

You are left with -4x/-4. We can simplify this even further by dividing both sides of the fraction by -4/-4. The -4's cancel out and become 1's, so you are left with:

x

lisov135 [29]3 years ago
4 0

Answer:


Step-by-step explanation:

g(f(x)) means that wherever you see an x in g(x) you put f(x) in it's place. Read that sentence a couple of times until it makes sense.

g(x) = (x + 1)/-4

g(f(x)) = (f(x) + 1) / - 4           Now wherever you see f(x), put in -4x - 1

g(f(x)) = [(-4x - 1) + 1] / - 4     Remove ( )

g(f(x)) = [-4x - 1 + 1 ] / - 4

g(f(x)) = [-4x] / - 4                 Do the division

g(f(x)) = x

Neat problem. thanks for posting.


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The 180 falls between which two whole numbers? A) 11 and 12 B) 12 and 13 C) 13 and 14 D) 14 and 15
Umnica [9.8K]

Answer:

C) 13 and 14

Step-by-step explanation:

To find the answer, we need to check for all the options.

A) 11 and 12 = 11 *12 = 132

B) 12 and 13 = 12 *13 = 156

C) 13 and 14 = 13*14 = 182

D) 14 and 15 = 14*15 = 210

In which, C) is true.

It is 182 which falls in 180's

Therefore, answer is C) 13 and 14

Hope this will helpful.

Thank you.

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3 0
3 years ago
Someone please help me thank you
german

Answer:

4

Step-by-step explanation:

7x = x² - 8

=> x² - 7x - 8 = 0

use quadratic formula:

a = 1, b = -7, c = -8

x = \frac{-(1)±\sqrt{(-7)^{2} - 4(1)(-8) } }{2(1)} <em>(pls ignore the "A" I don't know why it's showing up)</em>

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