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ELEN [110]
3 years ago
7

What two numbers multiply to and add to -32 add to -4

Mathematics
2 answers:
Ket [755]3 years ago
7 0

Answer:

-36

Step-by-step explanation:

luda_lava [24]3 years ago
4 0

Answer:

-36!! <33

Step-by-step explanation:

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To find 40% of 75 and calculate 2 of 5 . 75 . Does her calculation Correct value for 40% of 75
pickupchik [31]

Answer:

Yes, her calculation is correct. The value of 40% of 75 is 30.

Step-by-step explanation:

The value of 40% of 75 is

\frac{40}{100}\times 75=\frac{3000}{100}=30

The value of \frac{2}{5} of 75 is

\frac{2}{5}\times 75=2\times 15=30

From the above calculation it is noticed that the value of 40% of 75 and \frac{2}{5} of 75 are same, therefore the calculation is correct and the  value of 40% of 75 is 30.

4 0
3 years ago
Read 2 more answers
Which three lengths could be the lengths of the sides of a triangle?
ZanzabumX [31]

Answer:

c

Step-by-step explanation:


5 0
3 years ago
C=2pir; r=4.6 find c
ratelena [41]

C = 2 * pi(3.14) * 4.6


C ~ 28.903

3 0
3 years ago
Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt
lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that d | a, d | b so there exists integers k,m such that a = kd and b = md. Then,

t = ax+by = (kd)x+(md)y = d(kx+my). Recall that since k,  x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0
3 years ago
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
3 years ago
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