Given that:
CI = ₹408
years = 2 years
Rate of interest = 4%
A = P{1+(R/100)}^
A-P = p{1+(R/100)}^n - P
I = P[1+(R/100)}^n - 1]
408 = P[{1+(4/100)²} - 1]
= P[{1+(1/25)²} - 1]
= P[(26/25)² - 1]
= P[(676/625) - 1]
= P[(676-625)/625]
408 = P(51/625)
P = 408*(625/51)
= 8*625 = 5000
Sum = 5000
Simple Interest (I) = (P*R)/100
= 5000*2*(4/100)
= 50*2*4 = 400
From the given above options, option (a) ₹400 is your correct answer.
Let's look at the difference in speed between the two: it's 39-15.6=23.4 km/h
(we can just subtract this because they are traveling in the same direction) - this means that it's as if the slower train (the freight) was in place and the passenger train was traveling at 23.4 km/h
No, the freighter left 3.9 hours earlier, during which it traveled
15.6*3.9=60.84 km
So they will meet when the passenger train will catch up on those 60.84 km.
It does it with 23.4 km/h so it will need:

So the freighter will be travellinf for 2.6 more hours than the other train - a total of (2.6+3.9=6.5) 6.5 hours!
Answer:


Step-by-step explanation:
Alejandro has read 28 pages so far and he can read 1 page per minute.
Again, Carly has read 12 pages so far and he can read 2 pages per minute.
If the variable N represents the number of pages read by the readers and T in minutes represents the time spent by the reader to read this number of pages, then
For Alejandro:
......... (1)
For Carly:
.......... (2)
So, the equations (1) and (2) gives the number of pages that Alejandro and Carly read. (Answer)
Answer:

Step-by-step explanation:



Answer: a) -6, b) 32, c) -48, d) 9, e) -12
Step-by-step explanation:
Since we have given that
A and B are 4 × 4 matrices.
Here,
det (A) = -3
det (B) = 2
We need to find the respective parts:
a) det (AB)

b) det (B⁵ )

c) det (2A)
Since we know that

so, it becomes,

d) 
Since we know that

so, it becomes,

e) det (B⁻¹AB)
As we know that

so, it becomes,

Hence, a) -6, b) 32, c) -48, d) 9, e) -12