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Anna35 [415]
3 years ago
9

Please help, I'll give brainiest!

Chemistry
1 answer:
Whitepunk [10]3 years ago
8 0

is it a word problem beacuse i cant see the image. Im really good a chem but if you can write the question in the commets il answer it in the comments

Explanation:

You might be interested in
Why do you think it is advantageous to use inert electrodes in the electrolysis process? ​
olga nikolaevna [1]

Answer:

The advantage of this technique is that purified water as well as deposited metals can be re-used. It is necessary to use an inert electrode, such as platinum, because there is no metal present to conduct the electrons from the anode to the cathode.

5 0
3 years ago
1. An oxide of chromium is found to have the following % composition: 68.4% Cr
abruzzese [7]

Answer:

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

                            Cr               :         O

                           1.32/1.32     :       1.98/1.32

                               1              :        1.5

Cr : O = 1 :  1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

6 0
3 years ago
He molecular formula mass of this compound is 180 amu . what are the subscripts in the actual molecular formula?
mezya [45]
I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.

Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol

Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6

Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
<em>Actual molecular formula = C₆H₁₂O₆</em>

5 0
3 years ago
What is the percent by mass of nahco3 in a solution containing 10 g of nahco3 dissolved in 400 ml of h2o?
Marat540 [252]
Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
7 0
3 years ago
Which of these describes an endothermic process?
oksian1 [2.3K]

Answer:

Put up the answer choices

Explanation:

endothermic means absorbing heat

5 0
3 years ago
Read 2 more answers
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