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charle [14.2K]
3 years ago
12

Modify the given fatty acid so that it represents the 18‑carbon fatty acid designated 18:2(Δ9,12). Draw any double bonds in the

cis configuration. Utlizise Groups when appropriate.

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

See explanation

Explanation:

In this case, we have to remember the meaning of the nomenclature "18:2Δ9,12".  Where 18 is the <u>number of carbon atom</u>s, 2 is the <u>number of double bonds,</u> and the numbers successive to Δ "delta" the position of the double bonds <u>starting</u> to count from the carboxylic -COOH end of the molecule.

In other words, the main functional group is a <u>carboxylic acid</u>. We have a total of 18 carbons. Additionally, we have 2 double bonds. On carbons 9 and 12.

Lets see figure 1

I hope it helps!

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If 39.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
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2 years ago
When a reaction has reached equilibrium... A. Q = K B. The rate of the forward reaction and the rate of the reverse reaction are
grin007 [14]

Answer:

The correct answer is option A.

Explanation:

Equilibrium is a state when rate of forward reaction is equal to the rate of backward reaction. The concentration of reactants and products becomes constant at this state.

The ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients is termed as Equilibrium constant. It is denoted by K_{eq}.

aA + bB \rightleftharpoons cC

K_{eq}=\frac{[C]^c}{[A]^a[B]^b}

4 0
2 years ago
An 85.0 g sample of iron requires 954 J of heat to raise its temperature 25.0°C. What is the specific heat of the iron? \
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Explanation:

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7 0
3 years ago
Cu + 2 AgNO3 + Cu(NO3)2 + 2Ag
Allushta [10]

Answer:

7.28 moles Ag°

Explanation:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Given 7.28 moles     7.28 moles

To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...

Limiting reactant determination:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Cu: 7.28 / 1  = 7.28

AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃

Solving Problem depends on AgNO₃; Cu will be in excess.

Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.

5 0
2 years ago
How many ruthenium atoms can you line up across across the tip of a finger that is 3.6 cm in length. A ruthenium atom has an ave
Fofino [41]

Answer:

1.0 × 10⁸ ruthenium atoms

Explanation:

Step 1: Calculate the diameter (d) of an atom of ruthenium

The diameter of an atom is twice its radius.

d = 2 × r = 2 x 178 pm = 356 pm

Step 2: Convert "d" to meters

We will use the conversion factor 1 m = 10¹² pm.

356 pm × 1 m/10¹² pm = 3.56 × 10⁻¹⁰ m

Step 3: Convert the distance of the tip of a finger (D) to meters

We will use the conversion factor 1 m = 10² cm.

3.6 cm × 1 m/10² cm = 0.036 m

Step 4: Calculate the number of atoms of ruthenium required

We will use the following expression.

D/d = 0.036 m/3.56 × 10⁻¹⁰ m = 1.0 × 10⁸

4 0
3 years ago
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