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FromTheMoon [43]
2 years ago
8

Help PLEASE, I am behind already.

Chemistry
1 answer:
Ratling [72]2 years ago
5 0

The factors to be kept constant in the experiment are:

  • temperature
  • volume of ice
  • pressure.

The greater the quantity of salt added, the faster the rate of the melting of ice.

<h3>How does the quantity of salt added affect the rate at which ice will melt?</h3>

The melting of ice when salt is added is due to the lowering of the melting point of ice by the salt.

The rate of the reaction is directly proportional to the concentration or amount of salt added.

Therefore, the greater the quantity of salt added, the faster the rate of the melting of ice.

The factors to be kept constant are:

  • temperature
  • volume of ice
  • pressure.

In conclusion, the rate of melting of ice increases with increase n the quantity of salt added.

Learn more about salt and melting of ice at: brainly.com/question/17118985

#SPJ1

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A company issued 6%, 15-year bonds with a face amount of $67 million. The market yield for bonds of similar risk and maturity is
mr Goodwill [35]

Answer:

Bond is expected to be sold at the face value .

Explanation

In cases where market interest rate of bond is lower than coupon rate of bond, the bond is issued at a premium. Reason being that company is giving higher  interest rate on bond , this higher rate of interest  increases the price of bond, thus, bond is issued at premium.

In a scenario where market interest rate of bond is higher than coupon rate of bond, the bond is issued at Discount. This is so in that company is not returning more than market rate, therefore, to compensate that, the sale value of bond is usually lower than face value.

If the Market rate and coupon rate is equal , then bond will be issued at face value.

Considering the given question, Coupon rate of bond is 6% and market rate is also 6%. In this question , Market yield is considered to be market rate .

Therefore, there is no need to calculate present value of interest payments and redemption value at maturity to calculate price of bond.

8 0
4 years ago
6. Find the number of molecules in 33.6 L of co, at STP? What is the name
Nataly [62]
Question 6 says CO2, not CO.

At STP, one mole of any gas occupies 22.4 L. So, at STP, 33.6 L of our gas contains (33.6 L)/(22.4 L/mol) = 1.5 moles.

One mole of any substance contains 6.022 × 10²³ particles, or in this case, molecules. So 1.5 moles contains (1.5 moles)(6.022 × 10²³ molecules/mole) = 9.03 × 10²³ molecules.

As you can see, in this case it doesn’t matter what the identity of the gas is. But it does matter when it comes to naming. If the substance is CO, as you’ve typed, its name is carbon monoxide. If the substance is CO2 as it’s presented in the image, then its name is carbon dioxide.
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3 years ago
I will give you a lot of points help me ASAP please I am begging you
dalvyx [7]

Answer:

hope this helps

Explanation:

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I would expect silane because all the rest have an overall dipole movement
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