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Novosadov [1.4K]
3 years ago
8

Can anyone explain how to solve this and what it’s asking?

Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer:

You basically have to subsitute 4 in the x's place. where ever there is a x you would put a 4 and what ever answer you end up would go into the box.

Step-by-step explanation:

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a community Center has three swimming pools.the water level of each pool is measured at 8:00pm each night.Two of the measurement
oee [108]
The answer would be 1 1/2
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3 years ago
Teach me the train track method of converting amounts 100 POINTS
melomori [17]
Https://www.youtube.com/watch?v=WNr31DGrOqw she's explain how to do it without you getting lost because if I told you you'd be lost 
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3 years ago
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Please Help Me :(​ I will mark brainlist too
kolbaska11 [484]

Answer:

The fan = x = 400

The heater = y = 3600

Step-by-step explanation:

Let the cost price of

The fan = x

The heater = y

Aaya bought a fan and a heater for Rs 4,000.

x + y = 4000

x = 4000 - y

He sold the fan at a profit of 25%

25% × x = 0.25x

And the heater at a loss of 5%.

5% × x = 0.05y

If he gained 7% on his total outlay, at

Hence:

0.25x + 0.05y = 7% × 4,000

0.25x + 0.05y = 280

Note:

x = 4000 - y

Hence:

0.25(4000 - y) + 0.05y = 280

1000 - 0.25y + 0.05y = 280

Collect like terms

-0.25y + 0.05y = 280 - 1000

-0.20y = -720

y = -720/0.20

y = 3600

x = 4000 - y

x = 4000 - 3600

x = 400

Hence, the price that he bought each item is given as:

The fan = x = 400

The heater = y = 3600

7 0
3 years ago
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

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3 years ago
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djyliett [7]
38 yard piece for each student and there are 16 students:

38*16=608

608 yards needed for your class
6 0
3 years ago
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