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2 years ago

Solve for x. Round to the nearest tenth.

Mathematics

1 answer:

Shkiper50 [21]2 years ago

5 0

Answer:

24.8

Step-by-step explanation:

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What is the x-intercept? <br> 2x-6y= 18

Wittaler [7]

The x-intercept is (9,0). Hope it help!

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3 years ago

In Exercise, evaluate each expression.<br> 643/4

Goshia [24]

Answer:

$\\ 64^{\frac{3}{4}} = 16\sqrt{2}$

Step-by-step explanation:

We need here to remember that:

$\\{(x^{a})}^{b} = x^{a * b}$

$\\{x^{a} * x^{b} = x^{a + b}$

Then,

$\\ 64^{\frac{3}{4}} = {(8^{2})}^{(\frac{3}{4})} = {{(2^{3})}^{2}}^\frac{3}{4}$

$\\ 64^{\frac{3}{4}} = {{2^{3}}^2}^\frac{3}{4} = 2^\frac{3*2*3}{4}$

$\\ 64^{\frac{3}{4}} = 2^\frac{2*3*3}{4} = 2^\frac{3*3}{2} = 2^\frac{9}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}}$

Since $\\ \frac{9}{2} = \frac{4}{2} + \frac{4}{2} + \frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}} = {2^{(\frac{4}{2} + \frac{4}{2} + \frac{1}{2})}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{4}{2}} * 2^{\frac{4}{2}} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{2} * 2^{2} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 4 * 4 * \sqrt{2} = 16 \sqrt{2}$

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3 years ago

Hi can someone plss help me checking my essay? (don't just say it is good ) I just wanted to know if it flows good and if Im giv

Kitty [74]

First off, why is this in the mathematics section lol. Anyways, the essay looks good, but you can remove some unnecessary information. The reader doesn't need to know that the author is 14. Knowing the age of an author won't help support your argument.

Also, you say, "For example during the pandemic situation there were some quick changes to it like the vaccines being made...".

I would say instead, "During the pandemic, there were some rapid changes that took place to correct the pandemic like the vaccines being made...". Other than that, the essay looks good!

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2 years ago

Lea and Rob are selling fruit for a school fundraiser. Customers can buy small boxes of orangesand large boxes of oranges. Lea s

MaRussiya [10]

The first step is to define the system of equations.

Take x and y as the cost of a small box and a large box respectively.

$\begin{gathered} 2x+y=12 \\ 3x+y=16 \end{gathered}$

Solve the system.

$\begin{gathered} 2x+y=12 \\ y=12-2x \\ 3x+y=16 \\ y=16-3x \end{gathered}$ $\begin{gathered} 12-2x=16-3x \\ 3x-2x=16-12 \\ x=4 \end{gathered}$ $\begin{gathered} y=12-2x \\ y=12-2\cdot4 \\ y=12-8 \\ y=4 \end{gathered}$

A small box costs $4 and a large box costs $4 too.

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1 year ago

Alan spent of his money. If he had €65 left, how much had he at first?

Virty [35]

117 because it is right

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3 years ago