Perpendicular = opposite sign and reciprocal slope
-4 slope turns into 1/4
Y = 1/4x + b
11 = 1/4(-16) + b
11 = -4 + b, b = 15
Solution: y = 1/4x + 15
Question 1. -3 + v5 = 0
Work : -3 + 5v = 0
5v = 3 ( divide )
answer v = 3/5
Question 2. 1 - 7B = -20
work : -7b = -20 - 1
-7b = -21 ( divide )
answer b = 3
question 3 : -k - 5 = 0
work : -k = 5
answer : k = - 5
Question 4 : -1 + 8a = 129
work : 8a = 129 + 1
8a = 130 (divide )
answer a = 65/4
Answer:
4x² - x
Step-by-step explanation:
Add:
3x² + 2x - 1
x² - 3x + 1
<h3>
Answer: 131 degrees</h3>
Work Shown:
(angle JIW) + (angle WIH) = angle JIH
(2x+8) + (101) = 11x + 10
2x+109 = 11x+10
2x-11x = 10-109
-9x = -99
x = -99/(-9)
x = 11
So,
- angle JIW = 2x+8 = 2*11+8 = 22+8 = 30 degrees
- angle WIH = 101 degrees
- angle JIH = 11x+10 = 11*11+10 = 121+10 = 131 degrees
The smaller angles add to 30+101 = 131 to confirm we have the correct answer.
For more information, check out the angle addition postulate.
Answer:
No
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
- A triangle with some side measure .
- The sides are 4 ,6,7.
And we need to tell whether it is a right angled triangle or not . It will be a right angled triangle if it follows the Pythagoras Theorem.
<u>Pythagoras</u><u> Theorem</u><u> </u><u>:</u><u>-</u><u> </u>
- In right angle triangle the sum of squares of the two smallest sides is equal to the square of the largest side .
Here the two smallest sides are 4 & 6 .
<u>Sum </u><u>of </u><u>Squares </u><u>of </u><u>4</u><u> </u><u>and </u><u>6</u><u> </u><u>:</u><u>-</u><u> </u>
4² + 6²
24 + 36
60
<u>Square</u><u> </u><u>of </u><u>7</u><u> </u><u>:</u><u>-</u><u> </u>
7²
49
<u>And </u><u>:</u><u>-</u><u> </u>
- They aren't equal. So the triangle is not a right angled triangle .
<u>Hence </u><u>the triangle is not a right angle triangle</u><u>.</u>