Answer:
Please check the explanation.
Step-by-step explanation:
Given the sequence
![40,\:10,\:\frac{5}{2},\:\frac{5}{8}](https://tex.z-dn.net/?f=40%2C%5C%3A10%2C%5C%3A%5Cfrac%7B5%7D%7B2%7D%2C%5C%3A%5Cfrac%7B5%7D%7B8%7D)
A geometric sequence has a constant ratio 'r' and is defined by
![\:a_n=a_0\cdot r^{n-1}](https://tex.z-dn.net/?f=%5C%3Aa_n%3Da_0%5Ccdot%20r%5E%7Bn-1%7D)
Computing the ratios of all the adjacent terms
![\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B40%7D%3D%5Cfrac%7B1%7D%7B4%7D%2C%5C%3A%5Cquad%20%5Cfrac%7B%5Cfrac%7B5%7D%7B2%7D%7D%7B10%7D%3D%5Cfrac%7B1%7D%7B4%7D%2C%5C%3A%5Cquad%20%5Cfrac%7B%5Cfrac%7B5%7D%7B8%7D%7D%7B%5Cfrac%7B5%7D%7B2%7D%7D%3D%5Cfrac%7B1%7D%7B4%7D)
The ratio of all the adjacent terms is the same and equal to
![r=\frac{1}{4}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B1%7D%7B4%7D)
Thus, the given sequence is a geometric sequence.
As the first element of the sequence is
![a_1=40](https://tex.z-dn.net/?f=a_1%3D40)
Therefore, the nth term is calculated as
![\:a_n=a_0\cdot r^{n-1}](https://tex.z-dn.net/?f=%5C%3Aa_n%3Da_0%5Ccdot%20r%5E%7Bn-1%7D)
![a_n=40\left(\frac{1}{4}\right)^{n-1}](https://tex.z-dn.net/?f=a_n%3D40%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7Bn-1%7D)
Put n = 5 to find the next term
![a_5=40\left(\frac{1}{4}\right)^{5-1}](https://tex.z-dn.net/?f=a_5%3D40%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B5-1%7D)
![a_5=40\cdot \frac{1}{4^4}](https://tex.z-dn.net/?f=a_5%3D40%5Ccdot%20%5Cfrac%7B1%7D%7B4%5E4%7D)
![a_5=\frac{40}{4^4}](https://tex.z-dn.net/?f=a_5%3D%5Cfrac%7B40%7D%7B4%5E4%7D)
![=\frac{2^3\cdot \:5}{2^8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%5E3%5Ccdot%20%5C%3A5%7D%7B2%5E8%7D)
![a_5=\frac{5}{2^5}](https://tex.z-dn.net/?f=a_5%3D%5Cfrac%7B5%7D%7B2%5E5%7D)
![a_5=\frac{5}{32}](https://tex.z-dn.net/?f=a_5%3D%5Cfrac%7B5%7D%7B32%7D)
now, Put n = 6 to find the 6th term
![a_6=40\left(\frac{1}{4}\right)^{6-1}](https://tex.z-dn.net/?f=a_6%3D40%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B6-1%7D)
![a_6=40\cdot \frac{1}{4^5}](https://tex.z-dn.net/?f=a_6%3D40%5Ccdot%20%5Cfrac%7B1%7D%7B4%5E5%7D)
![a_6=\frac{40}{4^5}](https://tex.z-dn.net/?f=a_6%3D%5Cfrac%7B40%7D%7B4%5E5%7D)
![=\frac{2^3\cdot \:5}{2^{10}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%5E3%5Ccdot%20%5C%3A5%7D%7B2%5E%7B10%7D%7D)
![a_6=\frac{5}{2^7}](https://tex.z-dn.net/?f=a_6%3D%5Cfrac%7B5%7D%7B2%5E7%7D)
![a_6=\frac{5}{128}](https://tex.z-dn.net/?f=a_6%3D%5Cfrac%7B5%7D%7B128%7D)
Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:
Here you have to find which each variable is, for this you start of picking one equation,
x + 2y + 6z = 4
-3x + 2y - 2 = -4
4x + 2z = 16
depending the equation you pick you multiply that by a certain number that will give you the opposite of one of the other equations,
-1(x + 2y + 6z = 4)
= -x -2y - 6z = -4
With this you add or subtract it with the equation that has the same number or variable, or both,
In this case it will be the equation,
-3x + 2y + 6z = 4
You can use this one or the third equation since both have a positive 2y which will cancel with -2y from the new equation,
-x - 2y - 6z = -4
-3x + 2y -z = -4
= -4x -7z = -8
Now you since you just eliminated the variable (y) you now have 2 variables, and the last equation has only 2 variables, meaning now you find the answer to those to equations,
-4x -7z = -8
4x + 2z = 16
= -5z = 8
Now leave the variable by itself,
z = 8/5
Now you found the variable (z), with this just substitute on one of the equations we used to find (z) so you can find (x), after that substitute those answered to on of the original equations so you can find (y)
Answer:
300,000,000 or three hundred million
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
We know that all lengths in a rhombus are equal so we make the 2 equations equal to each other, then solve for x:
![4x-6=5x-10](https://tex.z-dn.net/?f=4x-6%3D5x-10)
![5x-4x=10-6](https://tex.z-dn.net/?f=5x-4x%3D10-6)
![x=4](https://tex.z-dn.net/?f=x%3D4)
x=4
Answer:
UB: 375
Step-by-step explanation:
370mm to 2 sig figs..
UB: 375
LB:365
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