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2 years ago

3y=2x+3 Solve for y :D

Mathematics

2 answers:

In-s [12.5K]2 years ago

8 0

Answer:

y = 2x/3 + 1

Step-by-step explanation:

baherus [9]2 years ago

6 0

Answer:

y = 2 x/3 + 1

Step-by-step explanation:

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Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis

Mariana [72]

Answer:

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago

From the side view, a gymnastics mat forms a right triangle with other angles measuring 60° and 30°. The gymnastics mat extends

valkas [14]

Answer: The mat is 4.33 ft high off the ground.

Step-by-step explanation:

Since we have given that

Angle of elevation with the first triangle = 30°

Angle of elevation with the second triangle = 60°

Length at which gymnastics mat extends across the floor = 5 feet

so, As shown in the figure:

We need to find the height of the mat off the ground.

If CD = 5 ft,

Let, AB = y, DC = x.

In Δ ABC,

$\tan 60^\circ=\frac{AB}{BC}\\\\\frac{\sqrt{3}}{2}=\frac{y}{x}\\\\x=\frac{y}{\sqrt{3}}$

Similarly, in Δ ACD,

$\tan 30^\circ=\frac{AB}{BD}\\\\\frac{1}{\sqrt{3}}=\frac{y}{x+5}\\\\\frac{1}{\sqrt{3}}=\frac{y}{\frac{y}{\sqrt{3}}+5}\\\\\frac{1}{\sqrt{3}}=\frac{y\sqrt{3}}{y+5\sqrt{3}}\\\\3y=y+5\sqrt{3}\\\\2y=5\sqrt{3}\\\\y=\frac{5\sqrt{3}}{2}\\\\y=4.33\ ft$

Hence, the mat is 4.33 ft high off the ground.

5 0

3 years ago

Read 2 more answers

PLEASE HELP HURRY!!!!!!!

Charra [1.4K]

As it has been given that $x=4+5i$ , $y=2-9i$ .

We need to find the value of the following:

(i) $4x-y$ , substituting the value of 'x' and 'y' in the expression, we get:

$4(4+5i)-(2-9i)=4\times 4+4\times 5i-2+9i=16+20i-2+9i$

$=14+29i$

So, $4x-y=14+29i$

(ii) $-x+3y$ , substituting the value of 'x' and 'y' in the expression, we get:

$-(4+5i)+3(2-9i)=-4-5i+3\times 2-3 \times 9i=-4-5i+6-27i$

$=2-32i$

So, $-x+3y=2-32i$

(iii) $x \times y$ , we need to substitute the value of 'x' and 'y' in the expression, for this, we can use distributive property of multiplication that says,